In the following figure, the horizontal surface on which this block slides is frictionless. If the two forces acting on it each have magnitude F = 35.0 N, and M = 17.0 kg, what is the magnitude of the resulting acceleration of the block (in m/s?)? 30°

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

In the following figure, the horizontal surface on which this block slides is frictionless. If the two forces acting on it each have a magnitude \( F = 35.0 \, \text{N} \), and \( M = 17.0 \, \text{kg} \), what is the magnitude of the resulting acceleration of the block (in \( \text{m/s}^2 \))?

**Diagram Explanation:**

- A block labeled \( M \) is positioned on a horizontal surface, indicating it is free to slide.
- There are two forces acting on the block:
  - The first force \( \vec{F} \) is angled \( 30^\circ \) above the horizontal, directed towards the block.
  - The second force \( \vec{F} \) is horizontal, pointing to the right.
  
The diagram represents the setup for calculating the net acceleration of the block using Newton's laws of motion, considering the decomposition of forces into horizontal components. The surface is specified as frictionless, suggesting that only the given forces contribute to the block's motion in this scenario.
Transcribed Image Text:**Problem Statement:** In the following figure, the horizontal surface on which this block slides is frictionless. If the two forces acting on it each have a magnitude \( F = 35.0 \, \text{N} \), and \( M = 17.0 \, \text{kg} \), what is the magnitude of the resulting acceleration of the block (in \( \text{m/s}^2 \))? **Diagram Explanation:** - A block labeled \( M \) is positioned on a horizontal surface, indicating it is free to slide. - There are two forces acting on the block: - The first force \( \vec{F} \) is angled \( 30^\circ \) above the horizontal, directed towards the block. - The second force \( \vec{F} \) is horizontal, pointing to the right. The diagram represents the setup for calculating the net acceleration of the block using Newton's laws of motion, considering the decomposition of forces into horizontal components. The surface is specified as frictionless, suggesting that only the given forces contribute to the block's motion in this scenario.
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