A block is pushed across a horizontal surface by the force shown. If the coefficient of kinetic friction between the block and the surface is 0.2, F = 29 N, theta = 32°, and M = 3 kg, what is the magnitude of the acceleration of the block?
A block is pushed across a horizontal surface by the force shown. If the coefficient of kinetic friction between the block and the surface is 0.2, F = 29 N, theta = 32°, and M = 3 kg, what is the magnitude of the acceleration of the block?
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The free body diagram of the system is given below:
The horizontal forces acting on the block are horizontal component of applied force , which is , acting in the positive x-direction and the frictional force , which is , acting in the negative x-direction , where is the applied force , is the angle , is the coefficient of kinetic friction , is the mass of the block and is the acceleration due to gravity .
According to Newton's second law of motion , the horizontal acceleration is calculated by using the formula .
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