In the following figure R1=100 Q, R2=200 2, and R3=300 Q. You are given that in this circuit Is=100 mA. Note that I am giving you Is in this problem that is different from the past problems just in case you didn't calculate it correctly before. Using the current divider method, what is the current 1? +. Vs R1 R2. R3 I I2 33.3 mA 54.5 mA 27.3 mA 18.2 mA
In the following figure R1=100 Q, R2=200 2, and R3=300 Q. You are given that in this circuit Is=100 mA. Note that I am giving you Is in this problem that is different from the past problems just in case you didn't calculate it correctly before. Using the current divider method, what is the current 1? +. Vs R1 R2. R3 I I2 33.3 mA 54.5 mA 27.3 mA 18.2 mA
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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If two resistors are connected in parallel than total resistance is (R1×R2)/(R1+R2).
By current division rule
If two resistors R1 and R2 are connected across current source I than by current division rule
Current in resistor R1 is I×(R2)/(R1+R2)
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