Which of the following is equivalent to Watts? Select all that apply Amps squared. Ohms Amps . Ohms Volts . Amps Volts squared / Ohms For loop CEFDC, what is the total voltage with 40 V for V4 , 80 V for V5 , and including 120 V for V3 ? V, = 30 V R, = 5 0 R¸ = 10 N E |4 = 6 A Iz = 2 A I4s = 4 A R = 60 Ω V3 R5 = 20 Ω Vs V, = 240 V Iz = 2 A | = 6 A |Ias = 4 A R, = 15 N V = 90 V 120V 80V 240V OV

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Which of the following is equivalent to Watts?
Select all that apply
Amps squared . Ohms
Amps . Ohms
Volts . Amps
Volts squared / Ohms
For loop CEFDC, what is the total voltage with 40 V for V4 , 80 V for V5 , and
including 120 V for V3 ?
V, = 30 V
R, = 5 N
R¸ = 10 N
E
|4 = 6 A
Iz = 2 A
I45
4 A
R3 =
60 N
R, =
20 Ω
V3
V, = 240 V
Iz = 2 A
|, = 6 A
Is = 4 A
в
R = 15 N
V = 90 V
120V
80V
240V
ov
Transcribed Image Text:Which of the following is equivalent to Watts? Select all that apply Amps squared . Ohms Amps . Ohms Volts . Amps Volts squared / Ohms For loop CEFDC, what is the total voltage with 40 V for V4 , 80 V for V5 , and including 120 V for V3 ? V, = 30 V R, = 5 N R¸ = 10 N E |4 = 6 A Iz = 2 A I45 4 A R3 = 60 N R, = 20 Ω V3 V, = 240 V Iz = 2 A |, = 6 A Is = 4 A в R = 15 N V = 90 V 120V 80V 240V ov
The total resistance of a series circuit:
O increases as more loads are connected in series.
O is the quotient of the total voltage and the total current.
O decreases as more loads are connected in series.
O is the sum of the individual load resistances.
For the circuit shown, the voltage drop across resistor R3 would be:
IT
R2= 220 12
13
14
R =
600
R3=
100
30 V
400
O 22V.
O 10v
O BV
A 12V
For the circuit shown, the current flow through resistor R1 would be:
IT R2= 220 12
R3=
100
R4=
400
30 V
600
O BA
E 1.5A
O 6A
E 0.5A
Transcribed Image Text:The total resistance of a series circuit: O increases as more loads are connected in series. O is the quotient of the total voltage and the total current. O decreases as more loads are connected in series. O is the sum of the individual load resistances. For the circuit shown, the voltage drop across resistor R3 would be: IT R2= 220 12 13 14 R = 600 R3= 100 30 V 400 O 22V. O 10v O BV A 12V For the circuit shown, the current flow through resistor R1 would be: IT R2= 220 12 R3= 100 R4= 400 30 V 600 O BA E 1.5A O 6A E 0.5A
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