In the following acid-base titration experiment NaOH(aq) + HNO3(aq) ———> NaNO3(aq) + H2O(1). What is the molarity of the HNO3 solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of HNO3? (a) 0.157 M (b) 0.0842 M (c) 3.978 M (d) 0.0157 M

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In the following acid-base titration experiment NaOH(aq) + HNO3(aq) ———> NaNO3(aq) + H2O(1). What is the molarity of the HNO3 solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of HNO3? (a) 0.157 M (b) 0.0842 M (c) 3.978 M (d) 0.0157 M
**Question 8:**

In the following acid-base titration experiment:

\[ \text{NaOH(aq) + HNO}_3\text{(aq)} \rightarrow \text{NaNO}_3\text{(aq)} + \text{H}_2\text{O(l)} \]

What is the molarity of the \(\text{HNO}_3\) solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of \(\text{HNO}_3\)?

- \(0.157 \, \text{M}\)
- \(0.0842 \, \text{M}\)
- \(3.978 \, \text{M}\)
- \(0.0157 \, \text{M}\)

**Question 9:**

In the following acid-base titration experiment:

\[ \text{CH}_3\text{COOH (aq) + NaOH (aq)} \rightarrow \text{CH}_3\text{COONa (aq) + H}_2\text{O (l)} \]

What is the molarity of the NaOH solution if 11.6 mL of 3.0 M acetic acid is required to neutralize the sodium hydroxide in 25.00 mL of solution?

- \(0.65 \, \text{M}\)
- \(6.5 \, \text{M}\)
- \(96.6 \, \text{M}\)
- \(1.392 \, \text{M}\)
Transcribed Image Text:**Question 8:** In the following acid-base titration experiment: \[ \text{NaOH(aq) + HNO}_3\text{(aq)} \rightarrow \text{NaNO}_3\text{(aq)} + \text{H}_2\text{O(l)} \] What is the molarity of the \(\text{HNO}_3\) solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of \(\text{HNO}_3\)? - \(0.157 \, \text{M}\) - \(0.0842 \, \text{M}\) - \(3.978 \, \text{M}\) - \(0.0157 \, \text{M}\) **Question 9:** In the following acid-base titration experiment: \[ \text{CH}_3\text{COOH (aq) + NaOH (aq)} \rightarrow \text{CH}_3\text{COONa (aq) + H}_2\text{O (l)} \] What is the molarity of the NaOH solution if 11.6 mL of 3.0 M acetic acid is required to neutralize the sodium hydroxide in 25.00 mL of solution? - \(0.65 \, \text{M}\) - \(6.5 \, \text{M}\) - \(96.6 \, \text{M}\) - \(1.392 \, \text{M}\)
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