In the figure the ideal batteries have emfs & = 24 V and 8, = 10.0V and the resistors have resistances R, = 4.9 Q and R2 = 8.1 Q. What are (a) the current, the energy dissipation rate in (b) resistor 1 and (c) resistor 2, and the energy transfer rate in (d) battery 1 and (e) battery 2? Is energy being supplied or absorbed by (f) battery 1 and (g) battery 2? R1 (a) Number Units (b) Number Units (c) Number Units (d) Number Units Units (e) Number

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DO NOT ANSWER F AND G
In the figure the ideal batteries have emfs & = 24 V and 8, = 10.0V
and the resistors have resistances R, = 4.9 0 and R2 = 8.10. What are
(a) the current, the energy dissipation rate in (b) resistor 1and (c)
resistor 2, and the energy transfer rate in (d) battery 1 and (e) battery
2? Is energy being supplied or absorbed by (f) battery 1 and (g) battery
2?
(a) Number
Units
(b) Number
Units
(c) Number
Units
(d) Number
Units
(e) Number
Units
Transcribed Image Text:In the figure the ideal batteries have emfs & = 24 V and 8, = 10.0V and the resistors have resistances R, = 4.9 0 and R2 = 8.10. What are (a) the current, the energy dissipation rate in (b) resistor 1and (c) resistor 2, and the energy transfer rate in (d) battery 1 and (e) battery 2? Is energy being supplied or absorbed by (f) battery 1 and (g) battery 2? (a) Number Units (b) Number Units (c) Number Units (d) Number Units (e) Number Units
Expert Solution
Step 1

Ohm's law: The voltage across a conductor is directly proportional to the flowing current through it. 

The power is define by multiplication of the voltage across a circuit element by the current flowing through it.

 

Given data:

emf, ε1=24 V

emf, ε2=10 V

Resistance, R1=4.9 Ω

Resistance, R2=8.1 Ω

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