In the figure shown, solve for the theoretical velocity of the jet, the actual velocity and the discharge through the orifice considering the following: a) p₁ =P₂ =0 h = 5 m of oil Do = 5 cm b) p₁ = h = 5 m of water P₂ = 0 Do = 5 cm c) p₁ = 70 kPa P2=0 C=1.00 (rounded) C₁ = 0.97 C=0.62 (sharp-edged) C₁ = 0.98 C=C 0.95 (rounded) Do D₁ = 7.5 cm h=1.60 m (liquid with sp. gr. = 3) h L.S. P2 2 L.S.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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In the figure shown, solve for the theoretical velocity of the jet, the
actual velocity and the discharge through the orifice considering the
following:
a) p1 = p2 = 0 Cc = 1.00 (rounded)
h = 5 m of oil Cv = 0.97
Do = 5 cm
b) p1 = p2 = 0 Cc = 0.62 (sharp-edged)
h = 5 m of water Cv = 0.98
Do = 5 cm
c) p1 = 70 kPa C = Cv = 0.95 (rounded)
p2 = 0 Do = 7.5 cm
h = 1.60 m (liquid with sp. gr. = 3)

In the figure shown, solve for the theoretical velocity of the jet, the
actual velocity and the discharge through the orifice considering the
following:
a) p₁ =P₂ =0
h = 5 m of oil
Do = 5 cm
b) p₁ =
h = 5 m of water
P₂ = 0
Do = 5 cm
c) p₁ = 70 kPa
P2=0
C=1.00 (rounded)
C₁ = 0.97
C=0.62 (sharp-edged)
C₁ = 0.98
C=C
0.95 (rounded)
Do
D₁ = 7.5 cm
h=1.60 m (liquid with sp. gr. = 3)
Transcribed Image Text:In the figure shown, solve for the theoretical velocity of the jet, the actual velocity and the discharge through the orifice considering the following: a) p₁ =P₂ =0 h = 5 m of oil Do = 5 cm b) p₁ = h = 5 m of water P₂ = 0 Do = 5 cm c) p₁ = 70 kPa P2=0 C=1.00 (rounded) C₁ = 0.97 C=0.62 (sharp-edged) C₁ = 0.98 C=C 0.95 (rounded) Do D₁ = 7.5 cm h=1.60 m (liquid with sp. gr. = 3)
h
L.S.
P2
2
L.S.
Transcribed Image Text:h L.S. P2 2 L.S.
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