In the figure, light is incident at angle 01 = 38° on a boundary between two transparent materials. Some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. If n = 1.30, n2 = 1.40, ng = 1.32 and n4 = 1.43, what is the value of (a) Os and (b) 04? %3D Air 14 (a) Os = Number i Units %3D (b) 04 = Number i Units

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The absolute tolerance is + 0.1
In the figure, light is incident at angle 01= 38° on a
boundary between two transparent materials.
Some of the light travels down through the next
three layers of transparent materials, while some
of it reflects upward and then escapes into the air.
If n = 1.30, n2 = 1.40, n3 = 1.32 and n4 = 1.43, what
is the value of (a) 05 and (b) 04?
Air
14
(a) O5 =
Number
Units
(b) 04 =
Number
Units
Transcribed Image Text:The absolute tolerance is + 0.1 In the figure, light is incident at angle 01= 38° on a boundary between two transparent materials. Some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. If n = 1.30, n2 = 1.40, n3 = 1.32 and n4 = 1.43, what is the value of (a) 05 and (b) 04? Air 14 (a) O5 = Number Units (b) 04 = Number Units
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