In the figure, block 2 of mass 2.70 kg oscillates on the end of a spring in SHM with a period of 20.00 ms. The position of the block is given by x (0.600 cm) cos(at + a/2). Block 1 of mass 5.40 kg slides toward block 2 with a velocity of magnitude 8.40 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time t-5.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? Number Units

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In the figure, block 2 of mass 2.70 kg oscillates on the end of a spring in SHM with a period of 20.00 ms. The position of
the block is given by x = (0.600 cm) cos(wt + x/2). Block 1 of mass 5.40 kg slides toward block 2 with a velocity of
magnitude 8.40 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time
t = 5.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after
the collision?
Number
Units
the tolerance is +/-5%
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Transcribed Image Text:In the figure, block 2 of mass 2.70 kg oscillates on the end of a spring in SHM with a period of 20.00 ms. The position of the block is given by x = (0.600 cm) cos(wt + x/2). Block 1 of mass 5.40 kg slides toward block 2 with a velocity of magnitude 8.40 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time t = 5.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? Number Units the tolerance is +/-5% Click if you would like to Show Work for this question: Open Show Work Question Attempts: 0 of 10 used SAVE FOR LATER SUBMIT ANSWER rivacy Policy | 9 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc. Version 4.24.20.1
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