In the figure, block 2 of mass 2.40 kg oscillates on the end of a spring in SHM with a period of 12.00 ms. The position of the block is given by x = (1.80 cm) cos(wt + n/2). Block 1 of mass 4.80 kg slides toward block 2 with a velocity of magnitude 6.90 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time t = 3.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? Number i Units k 00000 ◄►

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Chapter1: Units, Trigonometry. And Vectors
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In the figure, block 2 of mass 2.40 kg oscillates on the end of a spring in SHM with a period of 12.00 ms. The position of
the block is given by x = (1.80 cm) cos(wt+л/2). Block 1 of mass 4.80 kg slides toward block 2 with a velocity of
magnitude 6.90 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time
t = 3.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM
after the collision?
Number i
Units
k
00000
Transcribed Image Text:In the figure, block 2 of mass 2.40 kg oscillates on the end of a spring in SHM with a period of 12.00 ms. The position of the block is given by x = (1.80 cm) cos(wt+л/2). Block 1 of mass 4.80 kg slides toward block 2 with a velocity of magnitude 6.90 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time t = 3.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? Number i Units k 00000
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