In the figure, block 2 of mass 2.60 kg oscillates on the end of a spring in SHM with a period of 28.00 ms. The position of the block is given by x (1.40 cm) cos(at + n/2). Block 1 o mass 5.20 kg slides toward block 2 with a velocity of magnitude 3.50 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at timet - 7.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? 00000 Number Units the tolerance is +/-2%

icon
Related questions
Question
Chapter 15, Problem 34
Z Your answer is partially correct. Try again.
In the figure, block 2 of mass 2.60 kg oscillates on the end of a spring in SHM with a period of 28.00 ms. The position of the block is given by x = (1.40 cm) cos(@t + n/2). Block 1 of
mass 5.20 kg slides toward block 2 with a velocity of magnitude 3.50 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time t
= 7.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision?
Number
Units
the tolerance is +/-2%
Transcribed Image Text:Chapter 15, Problem 34 Z Your answer is partially correct. Try again. In the figure, block 2 of mass 2.60 kg oscillates on the end of a spring in SHM with a period of 28.00 ms. The position of the block is given by x = (1.40 cm) cos(@t + n/2). Block 1 of mass 5.20 kg slides toward block 2 with a velocity of magnitude 3.50 m/s, directed along the spring's length. The two blocks undergo a completely inelastic collision at time t = 7.00 ms. (The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? Number Units the tolerance is +/-2%
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS