In the figure below, two wheels A and B of radii rA=31.0 cm and rg=14.0 cm respectively are connected by a belt. A B If A accelerates uniformly from rest at 2.70 rad/s², find the angular speed of B after 8.40 s, assuming the wheels rotate without slipping.

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### Rotational Dynamics: Connected Wheels System

In the figure below, two wheels A and B have radii \( r_A = 31.0 \, \text{cm} \) and \( r_B = 14.0 \, \text{cm} \) respectively, and they are connected by a belt.

![Connected Wheels](image_url)

If wheel A accelerates uniformly from rest at \( 2.70 \, \text{rad/s}^2 \), determine the angular speed of wheel B after \( 8.40 \, \text{s} \), assuming the wheels rotate without slipping.

**Explanation of the Figure:**
- The figure depicts two wheels labeled A and B.
- Wheel A has a radius of 31.0 cm, and wheel B has a radius of 14.0 cm.
- The wheels are connected via a belt, ensuring that their tangential velocities are equal. This setup implies the wheels rotate without slipping.

**Problem Solution:**

To solve for the angular speed of wheel B after 8.40 seconds, follow these steps:

1. **Define the Relationship Between the Angular Velocities:**

Since the wheels are connected by a belt that does not slip, the tangential speed at the rims of wheels A and B will be the same:

\[ v_A = v_B \]

The tangential speed \( v \) is related to the angular speed \( \omega \) by the equation:

\[ v = r \omega \]

Therefore,

\[ r_A \omega_A = r_B \omega_B \]

2. **Find the Angular Speed of Wheel A:**

Using the angular acceleration and the time given, we can find the angular speed of wheel A after 8.40 seconds. The angular speed \( \omega_A \) is given by:

\[ \omega_A = \alpha t \]

where \( \alpha \) is the angular acceleration and \( t \) is the time.

Given \( \alpha = 2.70 \, \text{rad/s}^2 \) and \( t = 8.40 \, \text{s} \):

\[ \omega_A = 2.70 \, \text{rad/s}^2 \times 8.40 \, \text{s} = 22.68 \, \text{rad/s} \]

3. **Find the Angular Speed of Wheel B:**

Using the relationship between
Transcribed Image Text:### Rotational Dynamics: Connected Wheels System In the figure below, two wheels A and B have radii \( r_A = 31.0 \, \text{cm} \) and \( r_B = 14.0 \, \text{cm} \) respectively, and they are connected by a belt. ![Connected Wheels](image_url) If wheel A accelerates uniformly from rest at \( 2.70 \, \text{rad/s}^2 \), determine the angular speed of wheel B after \( 8.40 \, \text{s} \), assuming the wheels rotate without slipping. **Explanation of the Figure:** - The figure depicts two wheels labeled A and B. - Wheel A has a radius of 31.0 cm, and wheel B has a radius of 14.0 cm. - The wheels are connected via a belt, ensuring that their tangential velocities are equal. This setup implies the wheels rotate without slipping. **Problem Solution:** To solve for the angular speed of wheel B after 8.40 seconds, follow these steps: 1. **Define the Relationship Between the Angular Velocities:** Since the wheels are connected by a belt that does not slip, the tangential speed at the rims of wheels A and B will be the same: \[ v_A = v_B \] The tangential speed \( v \) is related to the angular speed \( \omega \) by the equation: \[ v = r \omega \] Therefore, \[ r_A \omega_A = r_B \omega_B \] 2. **Find the Angular Speed of Wheel A:** Using the angular acceleration and the time given, we can find the angular speed of wheel A after 8.40 seconds. The angular speed \( \omega_A \) is given by: \[ \omega_A = \alpha t \] where \( \alpha \) is the angular acceleration and \( t \) is the time. Given \( \alpha = 2.70 \, \text{rad/s}^2 \) and \( t = 8.40 \, \text{s} \): \[ \omega_A = 2.70 \, \text{rad/s}^2 \times 8.40 \, \text{s} = 22.68 \, \text{rad/s} \] 3. **Find the Angular Speed of Wheel B:** Using the relationship between
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