In the figure below, part of a long insulated wire carrying a current of I = 5.40 mA is bent into a circular section of radius R = 2.30 cm. What is the magnetic field at point C (the center of the circular section) under the following conditions? (a) Orientation A: The circular section lies in the xy plane (as shown in the figure above). B = nT i + nT + nTk (b) Orientation B: The circular section is given an additional 90° twist (around the pivot axis shown) so that it lies in the yz plane. %3D nT i +
In the figure below, part of a long insulated wire carrying a current of I = 5.40 mA is bent into a circular section of radius R = 2.30 cm. What is the magnetic field at point C (the center of the circular section) under the following conditions? (a) Orientation A: The circular section lies in the xy plane (as shown in the figure above). B = nT i + nT + nTk (b) Orientation B: The circular section is given an additional 90° twist (around the pivot axis shown) so that it lies in the yz plane. %3D nT i +
Related questions
Question

Transcribed Image Text:In the figure below, part of a long insulated wire carrying a current of I = 5.40 mA is bent into a circular section of radius R = 2.30 cm.
What is the magnetic field at point C (the center of the circular section) under the following conditions?
(a) Orientation A:
The circular section lies in the xy plane (as shown in the figure above).
nT i +
nT i-
nT
%3D
(b) Orientation B:
The circular section is given an additional 90° twist (around the pivot axis shown) so that it lies in the yz plane.
B
nT i +
j nT +
(c) If we treat the straight section of wire separately from the circular section, we can ask how they interact with each other.
If the circular section were free.to twist from rest, which would be its preferred orientation (relative to the straight section)?
Orientation B
Orientation A
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
