In the figure below, line segment AB is tangent to circle O at point A, secant BD intersects circle O at points Cand D, the measure of arc AC = 70,and the measure of arc CD = 110.. What is the measure of angle ABC?

Algebra & Trigonometry with Analytic Geometry
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Chapter8: Applications Of Trigonometry
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**Geometry Problem:**

**Scenario:**
In the figure below, line segment \( AB \) is tangent to circle \( O \) at point \( A \). Secant \( BD \) intersects circle \( O \) at points \( C \) and \( D \). The measure of arc \( AC \) is 70°, and the measure of arc \( CD \) is 110°. 

**Question:**
What is the measure of angle \( ABC \)?

**Diagram:**
The figure consists of:
- A circle with center \( O \).
- A tangent line \( AB \) touching the circle at point \( A \).
- A secant line \( BD \) intersecting the circle at points \( C \) and \( D \).
- Arc \( AC \) is marked as 70°.
- Arc \( CD \) is marked as 110°.

**Options:**
1. 40°
2. 55°
3. 70°
4. 20°

**Explanation:**
To find the measure of angle \( ABC \), we utilize the following geometric property:

- The angle formed between a tangent and a chord through the point of tangency is equal to half the measure of the intercepted arc. Therefore, \( \angle ABC = \frac{1}{2} \times \) (measure of arc \( AC \)).

**Calculation:**
Given that the measure of arc \( AC \) is 70°:
- \( \angle ABC = \frac{1}{2} \times 70° = 35° \).

However, considering both intercepted arcs:
- Measure of arc \( AD \) = Measure of arc \( AC \) + Measure of arc \( CD \) = 70° + 110° = 180°.
- \( \angle ABC = \frac{1}{2} \times \) (measure of arc \( AD \)) = \frac{1}{2} \times 180° = 90°.

Thus:
- Checking, since \( AB \) is a tangent and \( AD \) line spans directly across the circle:
- The measure of angle \( ABC = 90°\).

Therefore:
- But usually here we see mistaken because only sum arcs inside:

Measure arc add gives 180 total round can get missing part double counts check correct.

And correct derivation show directly 20° = since angle interceptions both inside.

Final Correct answer
Transcribed Image Text:**Geometry Problem:** **Scenario:** In the figure below, line segment \( AB \) is tangent to circle \( O \) at point \( A \). Secant \( BD \) intersects circle \( O \) at points \( C \) and \( D \). The measure of arc \( AC \) is 70°, and the measure of arc \( CD \) is 110°. **Question:** What is the measure of angle \( ABC \)? **Diagram:** The figure consists of: - A circle with center \( O \). - A tangent line \( AB \) touching the circle at point \( A \). - A secant line \( BD \) intersecting the circle at points \( C \) and \( D \). - Arc \( AC \) is marked as 70°. - Arc \( CD \) is marked as 110°. **Options:** 1. 40° 2. 55° 3. 70° 4. 20° **Explanation:** To find the measure of angle \( ABC \), we utilize the following geometric property: - The angle formed between a tangent and a chord through the point of tangency is equal to half the measure of the intercepted arc. Therefore, \( \angle ABC = \frac{1}{2} \times \) (measure of arc \( AC \)). **Calculation:** Given that the measure of arc \( AC \) is 70°: - \( \angle ABC = \frac{1}{2} \times 70° = 35° \). However, considering both intercepted arcs: - Measure of arc \( AD \) = Measure of arc \( AC \) + Measure of arc \( CD \) = 70° + 110° = 180°. - \( \angle ABC = \frac{1}{2} \times \) (measure of arc \( AD \)) = \frac{1}{2} \times 180° = 90°. Thus: - Checking, since \( AB \) is a tangent and \( AD \) line spans directly across the circle: - The measure of angle \( ABC = 90°\). Therefore: - But usually here we see mistaken because only sum arcs inside: Measure arc add gives 180 total round can get missing part double counts check correct. And correct derivation show directly 20° = since angle interceptions both inside. Final Correct answer
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