In the figure below, each charged particle is located at one of the four vertices of a square with side length = a. In the figure, A = 3, B = 5, and C = 5, and q > 0. Aq a ☐ a Bq a 9 Са (a) What is the expression for the magnitude of the electric field in the upper right corner of the square (at the location of q)? (Use the following as necessary: q, a, and k₂.) ^ E = i+ 19.07kg 27.07kg 4a² 4a² Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric field at this location. 35.2 × о Recall that the electric field is directed away from positive charges. Write the vector equation for the total electric field at charge q, and then use the components to find the angle. ⚫ (counterclockwise from the +x-axis) (b) Determine the expression for the total electric force exerted on the charge q. (Enter the magnitude. Use the following as necessary: q, a, and ke.) F = 19.07keq 4a -i + 27.07keg 4a Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric force on q. 35.2 Recall that the electric force is in the same direction as the electric field.° (counterclockwise from the +x-axis) (c) What If? How would the answers to parts (a) and (b) change if each of the four charges were negative with the same magnitude? Select all that apply. The force would be the same magnitude but opposite direction as the force in part (b). The electric field would be the same magnitude but opposite direction as the field in part (a). The force would be the same magnitude and direction as the force in part (b). The electric field would be the same magnitude and direction as the field in part (a).
In the figure below, each charged particle is located at one of the four vertices of a square with side length = a. In the figure, A = 3, B = 5, and C = 5, and q > 0. Aq a ☐ a Bq a 9 Са (a) What is the expression for the magnitude of the electric field in the upper right corner of the square (at the location of q)? (Use the following as necessary: q, a, and k₂.) ^ E = i+ 19.07kg 27.07kg 4a² 4a² Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric field at this location. 35.2 × о Recall that the electric field is directed away from positive charges. Write the vector equation for the total electric field at charge q, and then use the components to find the angle. ⚫ (counterclockwise from the +x-axis) (b) Determine the expression for the total electric force exerted on the charge q. (Enter the magnitude. Use the following as necessary: q, a, and ke.) F = 19.07keq 4a -i + 27.07keg 4a Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric force on q. 35.2 Recall that the electric force is in the same direction as the electric field.° (counterclockwise from the +x-axis) (c) What If? How would the answers to parts (a) and (b) change if each of the four charges were negative with the same magnitude? Select all that apply. The force would be the same magnitude but opposite direction as the force in part (b). The electric field would be the same magnitude but opposite direction as the field in part (a). The force would be the same magnitude and direction as the force in part (b). The electric field would be the same magnitude and direction as the field in part (a).
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter24: Electric Fields
Section: Chapter Questions
Problem 8PQ: For each sketch of electric field lines in Figure P24.8, compare the magnitude of the electric field...
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![In the figure below, each charged particle is located at one of the four vertices of a square with side length = a. In the figure, A = 3, B = 5, and C = 5, and q > 0.
Aq
a
☐
a
Bq
a
9
Са
(a) What is the expression for the magnitude of the electric field in the upper right corner of the square (at the location of q)? (Use the following as necessary: q, a, and k₂.)
^
E =
i+
19.07kg 27.07kg
4a²
4a²
Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric field at this location.
35.2
×
о
Recall that the electric field is directed away from positive charges. Write the vector equation for the total electric field at charge q, and then use the components to find the angle. ⚫ (counterclockwise from the +x-axis)
(b) Determine the expression for the total electric force exerted on the charge q. (Enter the magnitude. Use the following as necessary: q, a, and ke.)
F =
19.07keq
4a
-i +
27.07keg
4a
Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric force on q.
35.2
Recall that the electric force is in the same direction as the electric field.° (counterclockwise from the +x-axis)
(c) What If? How would the answers to parts (a) and (b) change if each of the four charges were negative with the same magnitude? Select all that apply.
The force would be the same magnitude but opposite direction as the force in part (b).
The electric field would be the same magnitude but opposite direction as the field in part (a).
The force would be the same magnitude and direction as the force in part (b).
The electric field would be the same magnitude and direction as the field in part (a).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc30753cc-6d78-4b03-8576-699452a9580c%2Fdbe68710-d2ac-4155-b827-01a3a639c980%2F4riirxn_processed.png&w=3840&q=75)
Transcribed Image Text:In the figure below, each charged particle is located at one of the four vertices of a square with side length = a. In the figure, A = 3, B = 5, and C = 5, and q > 0.
Aq
a
☐
a
Bq
a
9
Са
(a) What is the expression for the magnitude of the electric field in the upper right corner of the square (at the location of q)? (Use the following as necessary: q, a, and k₂.)
^
E =
i+
19.07kg 27.07kg
4a²
4a²
Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric field at this location.
35.2
×
о
Recall that the electric field is directed away from positive charges. Write the vector equation for the total electric field at charge q, and then use the components to find the angle. ⚫ (counterclockwise from the +x-axis)
(b) Determine the expression for the total electric force exerted on the charge q. (Enter the magnitude. Use the following as necessary: q, a, and ke.)
F =
19.07keq
4a
-i +
27.07keg
4a
Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric force on q.
35.2
Recall that the electric force is in the same direction as the electric field.° (counterclockwise from the +x-axis)
(c) What If? How would the answers to parts (a) and (b) change if each of the four charges were negative with the same magnitude? Select all that apply.
The force would be the same magnitude but opposite direction as the force in part (b).
The electric field would be the same magnitude but opposite direction as the field in part (a).
The force would be the same magnitude and direction as the force in part (b).
The electric field would be the same magnitude and direction as the field in part (a).
![](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc30753cc-6d78-4b03-8576-699452a9580c%2Fdbe68710-d2ac-4155-b827-01a3a639c980%2F1r8bgaa_processed.jpeg&w=3840&q=75)
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