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In the fbd how did he get 45 and 60 angles

In the fbd how did he get 45 and 60 angles

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In the fbd how did he get 45 and 60 angles

Problem 5.3 The beam is subjected to a load F = 400 N and is supported by the rope and the smooth surfaces at A and B. (a) Draw the free-body diagram of the beam. (b) What are the magnitudes of the reactions at A and B? FBD: A 3450 JF = 60° 45° A 1,5F →B= 2.5 13 13 -0.6 1.2 m 1.5 m - 1 m 'T B √/₂²A - ½ B=0 → √/2²A = ² B EF T EM - FCS) VB(25) BA (2)=O ² F(1,5) + (1.2)=0 m ½ B F - - 30° If we wanted I we could do Efy. B = 0.96 F = 383 N ⇒ A=271N
Transcribed Image Text:Problem 5.3 The beam is subjected to a load F = 400 N and is supported by the rope and the smooth surfaces at A and B. (a) Draw the free-body diagram of the beam. (b) What are the magnitudes of the reactions at A and B? FBD: A 3450 JF = 60° 45° A 1,5F →B= 2.5 13 13 -0.6 1.2 m 1.5 m - 1 m 'T B √/₂²A - ½ B=0 → √/2²A = ² B EF T EM - FCS) VB(25) BA (2)=O ² F(1,5) + (1.2)=0 m ½ B F - - 30° If we wanted I we could do Efy. B = 0.96 F = 383 N ⇒ A=271N
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