In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and AT||DM.Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as whole numbers. Decimals and non-reduced fractions will not be accepted.) В T M BT/TC (give your answer in numbers) by the Angle Bisector Theorem %3D ВТ %3 TC. (in numbers) Since M is the midpoint of BC СТ + TM = CM BM = BT + + TM = ВС TC + + TM TM = TC. (in numbers) ADİAC = by Parallel Lines Preserve Ratios + (in letters) AD = AC (in letters) AD = 18( ) (in numbers) AD = (in numbers reduced). 介
In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and AT||DM.Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as whole numbers. Decimals and non-reduced fractions will not be accepted.) В T M BT/TC (give your answer in numbers) by the Angle Bisector Theorem %3D ВТ %3 TC. (in numbers) Since M is the midpoint of BC СТ + TM = CM BM = BT + + TM = ВС TC + + TM TM = TC. (in numbers) ADİAC = by Parallel Lines Preserve Ratios + (in letters) AD = AC (in letters) AD = 18( ) (in numbers) AD = (in numbers reduced). 介
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
![In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and
AT||DM. Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as
whole numbers. Decimals and non-reduced fractions will not be accepted.)
ВТІТС —
(give your answer in numbers) by the Angle Bisector Theorem
BT =
TC. (in numbers)
Since M is the midpoint of BC
СТ
+ TM
= CM
= BM = BT + + TM
BC
ТC + TМ
%3D
TM :
TC. (in numbers)
AD/AC =
by Parallel Lines Preserve Ratios + (in letters)
AD = AC
(in letters)
AD = 18(
) (in numbers)
AD =
|(in numbers reduced).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12853c3d-16cf-4415-98db-5e1db331027b%2Fab83edbd-0275-4d8f-a00d-4fcaa8e84593%2Fjlsbpr5b_processed.png&w=3840&q=75)
Transcribed Image Text:In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and
AT||DM. Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as
whole numbers. Decimals and non-reduced fractions will not be accepted.)
ВТІТС —
(give your answer in numbers) by the Angle Bisector Theorem
BT =
TC. (in numbers)
Since M is the midpoint of BC
СТ
+ TM
= CM
= BM = BT + + TM
BC
ТC + TМ
%3D
TM :
TC. (in numbers)
AD/AC =
by Parallel Lines Preserve Ratios + (in letters)
AD = AC
(in letters)
AD = 18(
) (in numbers)
AD =
|(in numbers reduced).
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