In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and AT||DM.Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as whole numbers. Decimals and non-reduced fractions will not be accepted.) В T M BT/TC (give your answer in numbers) by the Angle Bisector Theorem %3D ВТ %3 TC. (in numbers) Since M is the midpoint of BC СТ + TM = CM BM = BT + + TM = ВС TC + + TM TM = TC. (in numbers) ADİAC = by Parallel Lines Preserve Ratios + (in letters) AD = AC (in letters) AD = 18( ) (in numbers) AD = (in numbers reduced). 介

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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ChapterP: Preliminary Concepts
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In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and
AT||DM. Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as
whole numbers. Decimals and non-reduced fractions will not be accepted.)
ВТІТС —
(give your answer in numbers) by the Angle Bisector Theorem
BT =
TC. (in numbers)
Since M is the midpoint of BC
СТ
+ TM
= CM
= BM = BT + + TM
BC
ТC + TМ
%3D
TM :
TC. (in numbers)
AD/AC =
by Parallel Lines Preserve Ratios + (in letters)
AD = AC
(in letters)
AD = 18(
) (in numbers)
AD =
|(in numbers reduced).
Transcribed Image Text:In the diagram below AB = 10, AC = 18, M is the midpoint of BC, AT is the bisector of ZBAC and AT||DM. Calculate AD. (Number answers must be entered as reduced fractions of the form a/b or as whole numbers. Decimals and non-reduced fractions will not be accepted.) ВТІТС — (give your answer in numbers) by the Angle Bisector Theorem BT = TC. (in numbers) Since M is the midpoint of BC СТ + TM = CM = BM = BT + + TM BC ТC + TМ %3D TM : TC. (in numbers) AD/AC = by Parallel Lines Preserve Ratios + (in letters) AD = AC (in letters) AD = 18( ) (in numbers) AD = |(in numbers reduced).
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