In the compound K2C1O4 , what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning Oxidation States are given as below) 1) The oxidation numbers of the atoms in a neutral molecule must add up to zero. 2) Group I → +1 ; Group II → +2 ; Group I → +3 3) Fluorine → -1 (always) Halogens - -1 (except in compounds with O and other halogens) 4) Hydrogen → +1 (except in metal hydrides, e.g. LiH, Rule 2 and H has -1) 5) Oxygen -2 (except in compounds with F, Rule 3) and compounds with 0-0 bonds (Rules 2 & 4) OA K:+2 , Cr:+2 ,O: -2 O B. K:+1 , Cr:+4 ,O: -2 ocK:+1 , Cr:+2 ,O: -2 O D.K:+2, Cr:+6 ,O: -2 K:+1 , Cr:+6 ,O: -2 O E.
In the compound K2C1O4 , what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning Oxidation States are given as below) 1) The oxidation numbers of the atoms in a neutral molecule must add up to zero. 2) Group I → +1 ; Group II → +2 ; Group I → +3 3) Fluorine → -1 (always) Halogens - -1 (except in compounds with O and other halogens) 4) Hydrogen → +1 (except in metal hydrides, e.g. LiH, Rule 2 and H has -1) 5) Oxygen -2 (except in compounds with F, Rule 3) and compounds with 0-0 bonds (Rules 2 & 4) OA K:+2 , Cr:+2 ,O: -2 O B. K:+1 , Cr:+4 ,O: -2 ocK:+1 , Cr:+2 ,O: -2 O D.K:+2, Cr:+6 ,O: -2 K:+1 , Cr:+6 ,O: -2 O E.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![In the compound K2CrO4 , what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning
Oxidation States are given as below)
1) The oxidation numbers of the atoms in a neutral molecule must add up to zero.
2) Group I- +1; Group II – +2; Group III → +3
3) Fluorine - -1 (always)
Halogens – -1 (except in compounds with O and other halogens)
4) Hydrogen-
+1 (except in metal hydrides, e.g. LiH, Rule 2 and H has -1)
5) Oxygen – -2 (except in compounds with F, Rule 3) and compounds with O-0 bonds (Rules 2 & 4)
OA K:+2 , Cr:+2 ,0: -2
OB. K:+1 , Cr:+4 ,0: -2
ocK:+1 , Cr:+2 ,O: -2
OD.K:+2 , Cr:+6 ,0: -2
O E. K:+1 , Cr:+6 ,0: -2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6cdf6781-7c75-44b7-982e-20c77f5084f6%2F086e6c36-d4bd-4972-9d53-cf33529cdb78%2Fpj4jnnm_processed.png&w=3840&q=75)
Transcribed Image Text:In the compound K2CrO4 , what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning
Oxidation States are given as below)
1) The oxidation numbers of the atoms in a neutral molecule must add up to zero.
2) Group I- +1; Group II – +2; Group III → +3
3) Fluorine - -1 (always)
Halogens – -1 (except in compounds with O and other halogens)
4) Hydrogen-
+1 (except in metal hydrides, e.g. LiH, Rule 2 and H has -1)
5) Oxygen – -2 (except in compounds with F, Rule 3) and compounds with O-0 bonds (Rules 2 & 4)
OA K:+2 , Cr:+2 ,0: -2
OB. K:+1 , Cr:+4 ,0: -2
ocK:+1 , Cr:+2 ,O: -2
OD.K:+2 , Cr:+6 ,0: -2
O E. K:+1 , Cr:+6 ,0: -2
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