A 10.8-g sample of a diprotic acid requires 160.5 mL of a 0.750 M NaOH solution for complete neutralization. Determine the molar mass of the acid. g/mol

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Problem Statement:**

A 10.8-g sample of a diprotic acid requires 160.5 mL of a 0.750 M NaOH solution for complete neutralization. Determine the molar mass of the acid.

**Answer:**

___ g/mol

**Explanation:**

- **Diprotic Acid:** An acid that can donate two protons (H⁺ ions) per molecule in a reaction.
- **Neutralization Reaction:** A chemical reaction in which an acid and a base react quantitatively to form water and a salt, resulting in a neutral solution.

To solve for the molar mass of the diprotic acid:

1. **Convert volume to liters:**
   \( 160.5 \, mL = 0.1605 \, L \)

2. **Calculate moles of NaOH:**
   \[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (in liters)} \]
   \[ \text{Moles of NaOH} = 0.750 \, M \times 0.1605 \, L = 0.12038 \, moles \]

3. **Determine moles of diprotic acid:**
   Each mole of diprotic acid reacts with 2 moles of NaOH.
   \[ \text{Moles of Diprotic Acid} = \frac{\text{Moles of NaOH}}{2} \]
   \[ \text{Moles of Diprotic Acid} = \frac{0.12038}{2} = 0.06019 \, moles \]

4. **Calculate molar mass of the diprotic acid:**
   \[ \text{Molar Mass} = \frac{\text{Mass of Sample}}{\text{Moles of Diprotic Acid}} \]
   \[ \text{Molar Mass} = \frac{10.8 \, g}{0.06019 \, moles} = 179.48 \, g/mol \]

Thus, the molar mass of the diprotic acid is approximately 179.48 g/mol.
Transcribed Image Text:**Problem Statement:** A 10.8-g sample of a diprotic acid requires 160.5 mL of a 0.750 M NaOH solution for complete neutralization. Determine the molar mass of the acid. **Answer:** ___ g/mol **Explanation:** - **Diprotic Acid:** An acid that can donate two protons (H⁺ ions) per molecule in a reaction. - **Neutralization Reaction:** A chemical reaction in which an acid and a base react quantitatively to form water and a salt, resulting in a neutral solution. To solve for the molar mass of the diprotic acid: 1. **Convert volume to liters:** \( 160.5 \, mL = 0.1605 \, L \) 2. **Calculate moles of NaOH:** \[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (in liters)} \] \[ \text{Moles of NaOH} = 0.750 \, M \times 0.1605 \, L = 0.12038 \, moles \] 3. **Determine moles of diprotic acid:** Each mole of diprotic acid reacts with 2 moles of NaOH. \[ \text{Moles of Diprotic Acid} = \frac{\text{Moles of NaOH}}{2} \] \[ \text{Moles of Diprotic Acid} = \frac{0.12038}{2} = 0.06019 \, moles \] 4. **Calculate molar mass of the diprotic acid:** \[ \text{Molar Mass} = \frac{\text{Mass of Sample}}{\text{Moles of Diprotic Acid}} \] \[ \text{Molar Mass} = \frac{10.8 \, g}{0.06019 \, moles} = 179.48 \, g/mol \] Thus, the molar mass of the diprotic acid is approximately 179.48 g/mol.
### Oxidation-Reduction Reactions

Specify which of the following are oxidation-reduction reactions, and if it is, identify the oxidizing agent, the reducing agent, the substance being oxidized, and the substance being reduced. If it is not, select No and leave the following boxes blank. Express your answers as chemical formulas. Omit states-of-matter.

#### Reactions:

**a.** 
\[ CH_4 + 3O_2 \rightarrow CO_2 + 2H_2O \]
- **Redox?**
- **Oxidizing Agent:**
- **Reducing Agent:**
- **Substance Oxidized:**
- **Substance Reduced:**

**b.** 
\[ 3AgNO_3 + Sc \rightarrow Sc(NO_3)_3 + 3Ag \]
- **Redox?**
- **Oxidizing Agent:**
- **Reducing Agent:**
- **Substance Oxidized:**
- **Substance Reduced:**
Transcribed Image Text:### Oxidation-Reduction Reactions Specify which of the following are oxidation-reduction reactions, and if it is, identify the oxidizing agent, the reducing agent, the substance being oxidized, and the substance being reduced. If it is not, select No and leave the following boxes blank. Express your answers as chemical formulas. Omit states-of-matter. #### Reactions: **a.** \[ CH_4 + 3O_2 \rightarrow CO_2 + 2H_2O \] - **Redox?** - **Oxidizing Agent:** - **Reducing Agent:** - **Substance Oxidized:** - **Substance Reduced:** **b.** \[ 3AgNO_3 + Sc \rightarrow Sc(NO_3)_3 + 3Ag \] - **Redox?** - **Oxidizing Agent:** - **Reducing Agent:** - **Substance Oxidized:** - **Substance Reduced:**
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