In the circuit, two loads are connected j2 Ω in parallel. Load1 absorbs an average power of 30 kW and 40 KVAR magnetizing reactive power. Load 2 absorbs 20 kVA a lagging power factor of Vs 0.6. The voltage at the terminals of the loads is 10020° V(ms). Compute the value of the capacitor that would correct the power factor to 1 if placed in parallel with the two loads.
In the circuit, two loads are connected j2 Ω in parallel. Load1 absorbs an average power of 30 kW and 40 KVAR magnetizing reactive power. Load 2 absorbs 20 kVA a lagging power factor of Vs 0.6. The voltage at the terminals of the loads is 10020° V(ms). Compute the value of the capacitor that would correct the power factor to 1 if placed in parallel with the two loads.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![In the circuit, two loads are connected
j2 Q
in parallel. Load 1 absorbs an average power of 30
kW and 40 KVAR magnetizing reactive power.
Load 2 absorbs 20 kVA a lagging power factor of
Vs
0.6. The voltage at the terminals of the loads is
10020° V(ms). Compute the value of the capacitor
that would correct the power factor to 1 if placed in
parallel with the two loads.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67862452-a2aa-4c8e-b749-391a734f8350%2Fe9fb477d-de8e-48b9-9f18-617f489ea2cd%2Fahaelk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In the circuit, two loads are connected
j2 Q
in parallel. Load 1 absorbs an average power of 30
kW and 40 KVAR magnetizing reactive power.
Load 2 absorbs 20 kVA a lagging power factor of
Vs
0.6. The voltage at the terminals of the loads is
10020° V(ms). Compute the value of the capacitor
that would correct the power factor to 1 if placed in
parallel with the two loads.
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