In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown. 20.0 1 170 E = ? 190 >6.0 2 20.0 1 25 V 3.0N 13 N 1.00 Part A Find the current through the ammeter A. ANSWER: I = A Part B What are the polarity and emf of the battery E, assuming it has negligible internal resistance? ANSWER: E = V
In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown. 20.0 1 170 E = ? 190 >6.0 2 20.0 1 25 V 3.0N 13 N 1.00 Part A Find the current through the ammeter A. ANSWER: I = A Part B What are the polarity and emf of the battery E, assuming it has negligible internal resistance? ANSWER: E = V
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please answer part A and part B.
![In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown.
20.0 1
170
E = ?
190
>6.0 2
20.0 1
25 V
3.0N
13 N
1.00
Part A
Find the current through the ammeter A.
ANSWER:
I =
A
Part B
What are the polarity and emf of the battery E, assuming it has negligible internal resistance?
ANSWER:
E =
V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74279ea1-eff5-4403-94c6-eaa833f0d034%2F46416ea7-41ec-4df0-a7be-a925104c79f9%2Fe6drjgq.png&w=3840&q=75)
Transcribed Image Text:In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown.
20.0 1
170
E = ?
190
>6.0 2
20.0 1
25 V
3.0N
13 N
1.00
Part A
Find the current through the ammeter A.
ANSWER:
I =
A
Part B
What are the polarity and emf of the battery E, assuming it has negligible internal resistance?
ANSWER:
E =
V
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