In the circuit of Fig. 7_1, what is Leq? 2H Leq = 7 H ○ Leq=17 H ○ Leq=5 H Leq = 15 H Leq=20 H Leq=32 H 4 H m 4H -Lea] O a 4H O b Fig. 7_1 m 10H 8H 2H
In the circuit of Fig. 7_1, what is Leq? 2H Leq = 7 H ○ Leq=17 H ○ Leq=5 H Leq = 15 H Leq=20 H Leq=32 H 4 H m 4H -Lea] O a 4H O b Fig. 7_1 m 10H 8H 2H
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Publisher:Robert L. Boylestad
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![In the circuit of Fig. 7_1, what is \( L_{\text{eq}} \)?
**Diagram Description:**
- The circuit includes several inductors:
- A 2H inductor in series with two 4H inductors in a parallel configuration.
- Another 4H inductor follows in series from point a to point b.
- From this point, a separate section has a 10H inductor connected in parallel with an 8H and a 2H inductor.
**Options for \( L_{\text{eq}} \) Calculation:**
- \( L_{\text{eq}} = 7 \, \text{H} \)
- \( L_{\text{eq}} = 17 \, \text{H} \)
- \( L_{\text{eq}} = 5 \, \text{H} \)
- \( L_{\text{eq}} = 15 \, \text{H} \)
- \( L_{\text{eq}} = 20 \, \text{H} \)
- \( L_{\text{eq}} = 32 \, \text{H} \)
**Understanding the Diagram:**
- Inductors in series are added directly.
- Inductors in parallel follow the reciprocal rule for calculating the equivalent inductance:
\[
\frac{1}{L_{\text{eq}}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3} + \ldots
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F849b5f85-1e18-473b-8772-ae9929e740d6%2F39bbae47-3fb6-4546-b8d9-661eb846e030%2Fzndrq1m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In the circuit of Fig. 7_1, what is \( L_{\text{eq}} \)?
**Diagram Description:**
- The circuit includes several inductors:
- A 2H inductor in series with two 4H inductors in a parallel configuration.
- Another 4H inductor follows in series from point a to point b.
- From this point, a separate section has a 10H inductor connected in parallel with an 8H and a 2H inductor.
**Options for \( L_{\text{eq}} \) Calculation:**
- \( L_{\text{eq}} = 7 \, \text{H} \)
- \( L_{\text{eq}} = 17 \, \text{H} \)
- \( L_{\text{eq}} = 5 \, \text{H} \)
- \( L_{\text{eq}} = 15 \, \text{H} \)
- \( L_{\text{eq}} = 20 \, \text{H} \)
- \( L_{\text{eq}} = 32 \, \text{H} \)
**Understanding the Diagram:**
- Inductors in series are added directly.
- Inductors in parallel follow the reciprocal rule for calculating the equivalent inductance:
\[
\frac{1}{L_{\text{eq}}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3} + \ldots
\]
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Step 1: Equivalent inductance
The question is about finding equivalent inductance.
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