In the benzene molecule, carbon atoms form a ring with alternating single and double bonds in between each of them. Each carbon atom forms one a bond with one carbon atom and one and one bond with another. The bonding electrons are delocalized over the entire molecule. Thus, benzene is a resonance hybrid of two equivalent structures, and the single and double bonds oscillate from one position to the other. bond order for a C-C bond = Submit *-* 17| ΑΣΦ H-C Calculate the bond order for one carbon-carbon bond in the benzene molecule, taking and bonding into consideration. Express your answer numerically. ► View Available Hint(s) C-H H-C C-H

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Chapter1: Chemical Foundations
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Part C
In the benzene molecule, carbon atoms form a ring with alternating single and double bonds in between each of them. Each carbon atom forms one o bond with one carbon atom and one o and one
bond with another. The bonding electrons are delocalized over the entire molecule. Thus, benzene is a resonance hybrid of two equivalent structures, and the single and double bonds oscillate from
one position to the other.
bond order for a C-C bond =
Submit
H
195| ΑΣΦ
H-C
H
H
C-H
H
H
H-C
Calculate the bond order for one carbon-carbon bond in the benzene molecule, taking o and bonding into consideration.
Express your answer numerically.
► View Available Hint(s)
H
C=C
H
C-H
H
Transcribed Image Text:Part C In the benzene molecule, carbon atoms form a ring with alternating single and double bonds in between each of them. Each carbon atom forms one o bond with one carbon atom and one o and one bond with another. The bonding electrons are delocalized over the entire molecule. Thus, benzene is a resonance hybrid of two equivalent structures, and the single and double bonds oscillate from one position to the other. bond order for a C-C bond = Submit H 195| ΑΣΦ H-C H H C-H H H H-C Calculate the bond order for one carbon-carbon bond in the benzene molecule, taking o and bonding into consideration. Express your answer numerically. ► View Available Hint(s) H C=C H C-H H
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