in th blånks below, show all of your work for this problem paper for later upload. Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl- from Zn(s) and Cl2(g), and then calculate the lattice energy for ZNCI2(s). Carefull label each step of the cycle in your sketch. Process kJ mol 1 Bond dissociation (Cl2(g)) 242 Heat of formation (ZNCI2(s)) Heat of sublimation (Zn(s) EA (CI(g)). IE (Zn(g)) IE2 (Zn(g)) -451 131 -349 906.4 1733.3 Enter your value in the first box and an appropriate unit of measure in the second box.
in th blånks below, show all of your work for this problem paper for later upload. Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl- from Zn(s) and Cl2(g), and then calculate the lattice energy for ZNCI2(s). Carefull label each step of the cycle in your sketch. Process kJ mol 1 Bond dissociation (Cl2(g)) 242 Heat of formation (ZNCI2(s)) Heat of sublimation (Zn(s) EA (CI(g)). IE (Zn(g)) IE2 (Zn(g)) -451 131 -349 906.4 1733.3 Enter your value in the first box and an appropriate unit of measure in the second box.
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Born-Haber Cycle Calculation for Lattice Energy of ZnCl₂(s)
In addition to filling in the blanks below, show all of your work for this problem on paper for later upload.
Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl₂(s) from Zn(s) and Cl₂(g), and then calculate the lattice energy for ZnCl₂(s). Carefully label each step of the cycle in your sketch.
#### Data Table:
| Process | Energy (kJ mol⁻¹) |
|----------------------------------|------------------|
| Bond dissociation (Cl₂(g)) | 242 |
| Heat of formation (ZnCl₂(s)) | -451 |
| Heat of sublimation (Zn(s)) | 131 |
| Electron Affinity (Cl(g)) | -349 |
| First Ionization Energy (IE₁) of Zn(g) | 906.4 |
| Second Ionization Energy (IE₂) of Zn(g) | 1733.3 |
### Instructions for Calculations:
1. **Bond Dissociation of Cl₂(g) to 2Cl(g):**
\[ \text{Energy} = 242 \, \text{kJ mol}⁻¹ \]
2. **Sublimation of Zn(s) to Zn(g):**
\[ \text{Energy} = 131 \, \text{kJ mol}⁻¹ \]
3. **Ionization of Zn(g) to Zn²⁺(g):**
\[ \text{First Ionization Energy} = 906.4 \, \text{kJ mol}⁻¹ \]
\[ \text{Second Ionization Energy} = 1733.3 \, \text{kJ mol}⁻¹ \]
4. **Electron Affinity of Cl(g) to Cl⁻(g):**
\[ \text{Energy} = -349 \, \text{kJ mol}⁻¹ \]
**Total Electron Affinity for 2 moles of Cl:**
\[ 2 \times (-349) = -698 \, \text{kJ mol}⁻¹ \]
5. **Heat of Formation of ZnCl₂(s):**
\[ \text{Energy} = -451 \, \text{kJ mol}⁻¹ \]
###](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb21ffba4-460f-41d0-866e-5be939c02582%2F1ebd8876-56f3-4218-b1c1-d30f261a032a%2Fnfj2as0o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Born-Haber Cycle Calculation for Lattice Energy of ZnCl₂(s)
In addition to filling in the blanks below, show all of your work for this problem on paper for later upload.
Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl₂(s) from Zn(s) and Cl₂(g), and then calculate the lattice energy for ZnCl₂(s). Carefully label each step of the cycle in your sketch.
#### Data Table:
| Process | Energy (kJ mol⁻¹) |
|----------------------------------|------------------|
| Bond dissociation (Cl₂(g)) | 242 |
| Heat of formation (ZnCl₂(s)) | -451 |
| Heat of sublimation (Zn(s)) | 131 |
| Electron Affinity (Cl(g)) | -349 |
| First Ionization Energy (IE₁) of Zn(g) | 906.4 |
| Second Ionization Energy (IE₂) of Zn(g) | 1733.3 |
### Instructions for Calculations:
1. **Bond Dissociation of Cl₂(g) to 2Cl(g):**
\[ \text{Energy} = 242 \, \text{kJ mol}⁻¹ \]
2. **Sublimation of Zn(s) to Zn(g):**
\[ \text{Energy} = 131 \, \text{kJ mol}⁻¹ \]
3. **Ionization of Zn(g) to Zn²⁺(g):**
\[ \text{First Ionization Energy} = 906.4 \, \text{kJ mol}⁻¹ \]
\[ \text{Second Ionization Energy} = 1733.3 \, \text{kJ mol}⁻¹ \]
4. **Electron Affinity of Cl(g) to Cl⁻(g):**
\[ \text{Energy} = -349 \, \text{kJ mol}⁻¹ \]
**Total Electron Affinity for 2 moles of Cl:**
\[ 2 \times (-349) = -698 \, \text{kJ mol}⁻¹ \]
5. **Heat of Formation of ZnCl₂(s):**
\[ \text{Energy} = -451 \, \text{kJ mol}⁻¹ \]
###
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