in th blånks below, show all of your work for this problem paper for later upload. Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl- from Zn(s) and Cl2(g), and then calculate the lattice energy for ZNCI2(s). Carefull label each step of the cycle in your sketch. Process kJ mol 1 Bond dissociation (Cl2(g)) 242 Heat of formation (ZNCI2(s)) Heat of sublimation (Zn(s) EA (CI(g)). IE (Zn(g)) IE2 (Zn(g)) -451 131 -349 906.4 1733.3 Enter your value in the first box and an appropriate unit of measure in the second box.

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### Born-Haber Cycle Calculation for Lattice Energy of ZnCl₂(s)

In addition to filling in the blanks below, show all of your work for this problem on paper for later upload.

Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl₂(s) from Zn(s) and Cl₂(g), and then calculate the lattice energy for ZnCl₂(s). Carefully label each step of the cycle in your sketch.

#### Data Table:

| Process                          | Energy (kJ mol⁻¹) |
|----------------------------------|------------------|
| Bond dissociation (Cl₂(g))       | 242              |
| Heat of formation (ZnCl₂(s))     | -451             |
| Heat of sublimation (Zn(s))      | 131              |
| Electron Affinity (Cl(g))        | -349             |
| First Ionization Energy (IE₁) of Zn(g) | 906.4      |
| Second Ionization Energy (IE₂) of Zn(g) | 1733.3    |

### Instructions for Calculations:

1. **Bond Dissociation of Cl₂(g) to 2Cl(g):**
   \[ \text{Energy} = 242 \, \text{kJ mol}⁻¹ \]

2. **Sublimation of Zn(s) to Zn(g):**
   \[ \text{Energy} = 131 \, \text{kJ mol}⁻¹ \]

3. **Ionization of Zn(g) to Zn²⁺(g):**
   \[ \text{First Ionization Energy} = 906.4 \, \text{kJ mol}⁻¹ \]
   \[ \text{Second Ionization Energy} = 1733.3 \, \text{kJ mol}⁻¹ \]

4. **Electron Affinity of Cl(g) to Cl⁻(g):**
   \[ \text{Energy} = -349 \, \text{kJ mol}⁻¹ \]

**Total Electron Affinity for 2 moles of Cl:**
\[ 2 \times (-349) = -698 \, \text{kJ mol}⁻¹ \]

5. **Heat of Formation of ZnCl₂(s):**
   \[ \text{Energy} = -451 \, \text{kJ mol}⁻¹ \]

###
Transcribed Image Text:### Born-Haber Cycle Calculation for Lattice Energy of ZnCl₂(s) In addition to filling in the blanks below, show all of your work for this problem on paper for later upload. Use the data provided to sketch the Born-Haber cycle for the formation of ZnCl₂(s) from Zn(s) and Cl₂(g), and then calculate the lattice energy for ZnCl₂(s). Carefully label each step of the cycle in your sketch. #### Data Table: | Process | Energy (kJ mol⁻¹) | |----------------------------------|------------------| | Bond dissociation (Cl₂(g)) | 242 | | Heat of formation (ZnCl₂(s)) | -451 | | Heat of sublimation (Zn(s)) | 131 | | Electron Affinity (Cl(g)) | -349 | | First Ionization Energy (IE₁) of Zn(g) | 906.4 | | Second Ionization Energy (IE₂) of Zn(g) | 1733.3 | ### Instructions for Calculations: 1. **Bond Dissociation of Cl₂(g) to 2Cl(g):** \[ \text{Energy} = 242 \, \text{kJ mol}⁻¹ \] 2. **Sublimation of Zn(s) to Zn(g):** \[ \text{Energy} = 131 \, \text{kJ mol}⁻¹ \] 3. **Ionization of Zn(g) to Zn²⁺(g):** \[ \text{First Ionization Energy} = 906.4 \, \text{kJ mol}⁻¹ \] \[ \text{Second Ionization Energy} = 1733.3 \, \text{kJ mol}⁻¹ \] 4. **Electron Affinity of Cl(g) to Cl⁻(g):** \[ \text{Energy} = -349 \, \text{kJ mol}⁻¹ \] **Total Electron Affinity for 2 moles of Cl:** \[ 2 \times (-349) = -698 \, \text{kJ mol}⁻¹ \] 5. **Heat of Formation of ZnCl₂(s):** \[ \text{Energy} = -451 \, \text{kJ mol}⁻¹ \] ###
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