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-in terms of temperature T(x,t), Fourier number Fo= at/L², and x/L, T-T To-Ts = Σ n=0 2(-1)" (n+1/2)π e-(n+1/2)²²Fo COS n+ cos (n + 1) = 2 Π L (3.44) T-Te To-Te = Σe-Fo n=1 2 sin λn λn + sin λncos λn 'n Χ cos λn 'n L

-in terms of temperature T(x,t), Fourier number Fo= at/L², and x/L, T-T To-Ts = Σ n=0 2(-1)" (n+1/2)π e-(n+1/2)²²Fo COS n+ cos (n + 1) = 2 Π L (3.44) T-Te To-Te = Σe-Fo n=1 2 sin λn λn + sin λncos λn 'n Χ cos λn 'n L

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Derive Equation 3.44 to other photo equation. Explain the key assumptions and introduce each steps. importance in determining the lamda values.

-in terms of temperature T(x,t), Fourier number Fo= at/L², and x/L, T-T To-Ts = Σ n=0 2(-1)" (n+1/2)π e-(n+1/2)²²Fo COS n+ cos (n + 1) = 2 Π L (3.44)
Transcribed Image Text:-in terms of temperature T(x,t), Fourier number Fo= at/L², and x/L, T-T To-Ts = Σ n=0 2(-1)" (n+1/2)π e-(n+1/2)²²Fo COS n+ cos (n + 1) = 2 Π L (3.44)
T-Te To-Te = Σe-Fo n=1 2 sin λn λn + sin λncos λn 'n Χ cos λn 'n L
Transcribed Image Text:T-Te To-Te = Σe-Fo n=1 2 sin λn λn + sin λncos λn 'n Χ cos λn 'n L
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