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In STEP 4, you charged the capacitor completely with the PSB set to 3.3V. Then you set the PSB to 5V and closed the switch in the charging circuit again. You should have seen the LED light again temporarily. Why did the LED light again? O The LED lit again because the capacitor had been discharged before the PSB was set to 5V, obscuring the purpose of this step in the lab. O The current that charges a capacitor is driven by the voltage across the circuit. When the potential difference between the two leads of a capacitor is the same as the voltage applied by the charging circuit, no more current flows to charge the capacitor. Increasing the voltage in the charging circuit allows more current to flow as the voltage across the capacitor rises to the new potential supplied by the circuit. O The 100µF capacitor is capable of storing approximately ten times more energy than the 1OuF capacitor used previously. In order to store the additional electrical energy, the charging voltage has to be applied across the capacitor for a longer period of time. The LED lights again while the capacitor continues to charge. O A charged capacitor is only compatible with the same voltage that charged it. In order to function with a 5V circuit instead of a 3.3V circuit, the capacitor had to be charged again with the appropriate voltage. The LED lights again as a result of starting over.

In STEP 4, you charged the capacitor completely with the PSB set to 3.3V. Then you set the PSB to 5V and closed the switch in the charging circuit again. You should have seen the LED light again temporarily. Why did the LED light again? O The LED lit again because the capacitor had been discharged before the PSB was set to 5V, obscuring the purpose of this step in the lab. O The current that charges a capacitor is driven by the voltage across the circuit. When the potential difference between the two leads of a capacitor is the same as the voltage applied by the charging circuit, no more current flows to charge the capacitor. Increasing the voltage in the charging circuit allows more current to flow as the voltage across the capacitor rises to the new potential supplied by the circuit. O The 100µF capacitor is capable of storing approximately ten times more energy than the 1OuF capacitor used previously. In order to store the additional electrical energy, the charging voltage has to be applied across the capacitor for a longer period of time. The LED lights again while the capacitor continues to charge. O A charged capacitor is only compatible with the same voltage that charged it. In order to function with a 5V circuit instead of a 3.3V circuit, the capacitor had to be charged again with the appropriate voltage. The LED lights again as a result of starting over.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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STEP 4: make sure the capacitor is fully charged using the PSB set to 3.3V. Then switch the OAB jumper to 5V and hold SW1 closed again until the LED goes out
### Understanding Capacitor Charging and LED Response In STEP 4, you charged the capacitor completely with the PSB set to 3.3V. Then you set the PSB to 5V and closed the switch in the charging circuit again. You should have seen the LED light again temporarily. Why did the LED light again? - **Option 1:** - **Explanation:** The LED lit again because the capacitor had been discharged before the PSB was set to 5V, obscuring the purpose of this step in the lab. - **Option 2:** - **Explanation:** The current that charges a capacitor is driven by the voltage across the circuit. When the potential difference between the two leads of a capacitor is the same as the voltage applied by the charging circuit, no more current flows to charge the capacitor. Increasing the voltage in the charging circuit allows more current to flow as the voltage across the capacitor rises to the new potential supplied by the circuit. - **Option 3:** - **Explanation:** The 100µF capacitor is capable of storing approximately ten times more energy than the 10µF capacitor used previously. In order to store the additional electrical energy, the charging voltage has to be applied across the capacitor for a longer period of time. The LED lights again while the capacitor continues to charge. - **Option 4:** - **Explanation:** A charged capacitor is only compatible with the same voltage that charged it. In order to function with a 5V circuit instead of a 3.3V circuit, the capacitor had to be charged again with the appropriate voltage. The LED lights again as a result of starting over. --- ### Detailed Explanation of the Concepts - **Capacitor and LED Interaction:** - Capacitors store electrical energy when connected to a power supply. - When the charging voltage is increased (e.g., from 3.3V to 5V), the capacitor requires charging to the new voltage level. - The LED lights up when there is current flow in the circuit, indicating charging activity in the capacitor. - **Potential Difference and Current Flow:** - A capacitor charges until its potential difference equals the applied voltage. - Upon increasing the applied voltage, the potential difference is again unsynchronized, allowing current to flow and, consequently, the LED to light up temporarily. - **Storage Capacity:** - Different capacitors have different energy storage capacities.
Transcribed Image Text:### Understanding Capacitor Charging and LED Response In STEP 4, you charged the capacitor completely with the PSB set to 3.3V. Then you set the PSB to 5V and closed the switch in the charging circuit again. You should have seen the LED light again temporarily. Why did the LED light again? - **Option 1:** - **Explanation:** The LED lit again because the capacitor had been discharged before the PSB was set to 5V, obscuring the purpose of this step in the lab. - **Option 2:** - **Explanation:** The current that charges a capacitor is driven by the voltage across the circuit. When the potential difference between the two leads of a capacitor is the same as the voltage applied by the charging circuit, no more current flows to charge the capacitor. Increasing the voltage in the charging circuit allows more current to flow as the voltage across the capacitor rises to the new potential supplied by the circuit. - **Option 3:** - **Explanation:** The 100µF capacitor is capable of storing approximately ten times more energy than the 10µF capacitor used previously. In order to store the additional electrical energy, the charging voltage has to be applied across the capacitor for a longer period of time. The LED lights again while the capacitor continues to charge. - **Option 4:** - **Explanation:** A charged capacitor is only compatible with the same voltage that charged it. In order to function with a 5V circuit instead of a 3.3V circuit, the capacitor had to be charged again with the appropriate voltage. The LED lights again as a result of starting over. --- ### Detailed Explanation of the Concepts - **Capacitor and LED Interaction:** - Capacitors store electrical energy when connected to a power supply. - When the charging voltage is increased (e.g., from 3.3V to 5V), the capacitor requires charging to the new voltage level. - The LED lights up when there is current flow in the circuit, indicating charging activity in the capacitor. - **Potential Difference and Current Flow:** - A capacitor charges until its potential difference equals the applied voltage. - Upon increasing the applied voltage, the potential difference is again unsynchronized, allowing current to flow and, consequently, the LED to light up temporarily. - **Storage Capacity:** - Different capacitors have different energy storage capacities.
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