I don't understand how the professor got these answers, Can someone help ?The answers were :2.38 = chi squareDegrees of freedom= 1P-value = between .2-.1Fail to Reject **Title: Analysis of Chromatid Participation in Sordaria Meiosis****Introduction:**In the study of Sordaria, a white pigmented haploid fungus was fused with a dark pigmented haploid fungus, forming a diploid cell which subsequently underwent meiosis. The focus of this experiment is to determine if all four chromatids participate equally in crossing over.**Observed Data:**The following numbers of asci were observed based on their pigmentation pattern:1. First pattern: 46 asci (3 white, 1 dark, 3 white, 1 dark).2. Second pattern: 93 asci (2 white, 2 dark, 2 white, 2 dark).3. Third pattern: 34 asci (1 white, 3 dark, 1 white, 3 dark).4. Fourth pattern: 48 asci (4 dark, 4 white).5. Fifth pattern: 104 asci (2 dark, 4 white, 2 dark).6. Sixth pattern: 40 asci (4 white, 4 dark).**Objective:**Perform a Chi-square test to evaluate whether all chromatids are involved equally in crossing over. The goal is to determine the Chi-square value, degrees of freedom (DF), P-value, and make a decision regarding the null hypothesis.**Graphical Explanation:**A diagram shows six rows, each representing a distinct ascus pattern, with circles symbolizing the spores. White circles are white pigments and dark circles indicate dark pigments. The numbers adjacent to each pattern illustrate the observed frequency of each pattern type. ---**Statistical Analysis:**1. **Null Hypothesis (H0):** All four chromatids participate equally in crossing over.2. **Chi-square Test:** Calculate the Chi-square value using observed and expected data.3. **Degrees of Freedom:** \( DF = n - 1 \) (where n is the number of categories).4. **P-value:** Evaluate using the Chi-square distribution table.5. **Decision:** Compare P-value with significance level (usually 0.05) to accept or reject H0.This experimental setup provides insights into genetic recombination processes and contributes to understanding chromatid behavior during meiosis in fungi.

Name: I don't understand how the professor got these answers, Can someone he
Uploaded: 2024-03-20T07:06:16.000Z
Channel: Bartleby
Description: I don't understand how the professor got these answers, Can someone help ?The answers were :2.38 = chi squareDegrees of freedom= 1P-value = between .2-.1Fail to Reject **Title: Analysis of Chromatid Participation in Sordaria Meiosis****Introduction:*