In section 3.5, read pages 315-319. -2 1 the repeated eigenvalue is A - 2 (A) For the example where A = -2 (B) If the initial condition for this system is Y (0) = (3, 0), then Vo and V1 Note: enter vectors horizontally surrounded by parentheses! Furthermore, the solution to the IVP would be Y(t)=( 3e 2t
In section 3.5, read pages 315-319. -2 1 the repeated eigenvalue is A - 2 (A) For the example where A = -2 (B) If the initial condition for this system is Y (0) = (3, 0), then Vo and V1 Note: enter vectors horizontally surrounded by parentheses! Furthermore, the solution to the IVP would be Y(t)=( 3e 2t
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Could someone please explain this for me?
![In section 3.5, read pages 315-319.
-2
1
(A) For the example where A =
the repeated eigenvalue is A = -2
- 2
(B) If the initial condition for this system is Y (0) = (3, 0), then
Vo
and V1
Note: enter vectors horizontally surrounded by parentheses!
Furthermore, the solution to the IVP would be
Ý (t)=( 3e 2t
V, 0
C) If the initial condition for this system is Y (0) = (6, 3), then
Vo =
and V,
and the solution to the IVP would be
Y(t)=( 6e-2t + 3te 2t
V 3e 2t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F803c8554-30d6-4115-9882-dc6eeac760d5%2Fb38274c9-7915-409a-8552-0f25404479a8%2F3rj3vy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In section 3.5, read pages 315-319.
-2
1
(A) For the example where A =
the repeated eigenvalue is A = -2
- 2
(B) If the initial condition for this system is Y (0) = (3, 0), then
Vo
and V1
Note: enter vectors horizontally surrounded by parentheses!
Furthermore, the solution to the IVP would be
Ý (t)=( 3e 2t
V, 0
C) If the initial condition for this system is Y (0) = (6, 3), then
Vo =
and V,
and the solution to the IVP would be
Y(t)=( 6e-2t + 3te 2t
V 3e 2t
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