In sample Prob. 5.03, what is the y- component of the acceleration of block H? same (magnitude & direction) as x- component of acceleration of block S b. same magnitude but in the perpendicular direction to the x- component of acceleration of block c. larger magnitude and perpendicular direction to the x-component of acceleration of block S, since it moves downwards d. smaller magnitude and same direction as x-component of acceleration of block S, since it is smaller weight than block S.

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Chapter1: Units, Trigonometry. And Vectors
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In sample Prob. 5.03, what is the y-
component of the acceleration of block H?
а.
same (magnitude & direction) as x-
component of acceleration of block
b.
same magnitude but in the
perpendicular direction to the x-
component of acceleration of block
c. larger magnitude and perpendicular
direction to the x-component of
acceleration of block S, since it
moves downwards
d. smaller magnitude and same
direction as x-component of
acceleration of block S, since it is
smaller weight than block S.
Transcribed Image Text:In sample Prob. 5.03, what is the y- component of the acceleration of block H? а. same (magnitude & direction) as x- component of acceleration of block b. same magnitude but in the perpendicular direction to the x- component of acceleration of block c. larger magnitude and perpendicular direction to the x-component of acceleration of block S, since it moves downwards d. smaller magnitude and same direction as x-component of acceleration of block S, since it is smaller weight than block S.
Sample Problem 5.03 Block on table, block hanging
Figure 5-12 shows a block S (the sliding block) with mass
M = 3.3 kg. The block is free to move along a horizontal
frictionless surface and connected, by a cord that wraps over
a frictionless pulley, to a second block H (the hanging
block), with mass m = 2.1 kg. The cord and pulley have neg-
ligible masses compared to the blocks (they are "massless").
The hanging block H falls as the sliding block S accelerates
to the right. Find (a) the acceleration of block S, (b) the ac-
celeration of block H, and (c) the tension in the cord.
Block S
Block H
Q What is this problem all about?
You are given two bodies-sliding block and hanging
block-but must also consider Earth, which pulls on both
bodies. (Without Earth, nothing would happen here.) A to-
tal of five forces act on the blocks, as shown in Fig. 5-13:
Figure 5-13 The forces acting on the two blocks of Fig, 5-12.
certain time, block S moves 1 mm to the right in that same
time. This means that the blocks move together and their
accelerations have the same magnitude a.
1. The cord pulls to the right on sliding block S with a force
of magnitude T.
2. The cord pulls upward on hanging block H with a force
of the same magnitude T. This upward force keeps block
H from falling freely.
Q How do I classify this problem? Should it suggest a par-
ticular law of physics to me?
Yes. Forces, masses, and accelerations are involved, and
they should suggest Newton's second law of motion, F=
ma. That is our starting key idea.
3. Earth pulls down on block S with the gravitational force
Fs, which has a magnitude equal to Mg.
4. Earth pulls down on block H with the gravitational force
Ft, which has a magnitude equal to mg.
5. The table pushes up on block S with a normal force Fy.
Q IfI apply Newton's second law to this problem, to whic
body should I apply it?
We focus on two bodies, the sliding block and the hangi
block. Although they are extended objects (they are r
points), we can still treat each block as a particle becau
every part of it moves in exactly the same way. A second b
idea is to apply Newton's second law separately to each blo
There is another thing you should note. We assume that
the cord does not stretch, so that if block H falls 1 mm in a
Sliding
block S
Q What about the pulley?
We cannot represent the pulley as a particle beca
different parts of it move in different ways. When we
cuss rotation, we shall deal with pulleys in de
Meanwhile, we eliminate the pulley from consideratio
assuming its mass to be negligible compared with
masses of the two blocks. Its only function is to chang
cord's orientation.
M
Frictionless
surface
Hanging
block H
Q OK. Now how do I apply Fnet = ma to the sliding b
Represent block S as a particle of mass M and dr
the forces that act on it, as in Fig. 5-14a. This is the b
free-body diagram. Next, draw a set of axes. It makes
Figure 5-12 A block S of mass M is connected to a block H of mass
m by a cord that wraps over a pulley.
Transcribed Image Text:Sample Problem 5.03 Block on table, block hanging Figure 5-12 shows a block S (the sliding block) with mass M = 3.3 kg. The block is free to move along a horizontal frictionless surface and connected, by a cord that wraps over a frictionless pulley, to a second block H (the hanging block), with mass m = 2.1 kg. The cord and pulley have neg- ligible masses compared to the blocks (they are "massless"). The hanging block H falls as the sliding block S accelerates to the right. Find (a) the acceleration of block S, (b) the ac- celeration of block H, and (c) the tension in the cord. Block S Block H Q What is this problem all about? You are given two bodies-sliding block and hanging block-but must also consider Earth, which pulls on both bodies. (Without Earth, nothing would happen here.) A to- tal of five forces act on the blocks, as shown in Fig. 5-13: Figure 5-13 The forces acting on the two blocks of Fig, 5-12. certain time, block S moves 1 mm to the right in that same time. This means that the blocks move together and their accelerations have the same magnitude a. 1. The cord pulls to the right on sliding block S with a force of magnitude T. 2. The cord pulls upward on hanging block H with a force of the same magnitude T. This upward force keeps block H from falling freely. Q How do I classify this problem? Should it suggest a par- ticular law of physics to me? Yes. Forces, masses, and accelerations are involved, and they should suggest Newton's second law of motion, F= ma. That is our starting key idea. 3. Earth pulls down on block S with the gravitational force Fs, which has a magnitude equal to Mg. 4. Earth pulls down on block H with the gravitational force Ft, which has a magnitude equal to mg. 5. The table pushes up on block S with a normal force Fy. Q IfI apply Newton's second law to this problem, to whic body should I apply it? We focus on two bodies, the sliding block and the hangi block. Although they are extended objects (they are r points), we can still treat each block as a particle becau every part of it moves in exactly the same way. A second b idea is to apply Newton's second law separately to each blo There is another thing you should note. We assume that the cord does not stretch, so that if block H falls 1 mm in a Sliding block S Q What about the pulley? We cannot represent the pulley as a particle beca different parts of it move in different ways. When we cuss rotation, we shall deal with pulleys in de Meanwhile, we eliminate the pulley from consideratio assuming its mass to be negligible compared with masses of the two blocks. Its only function is to chang cord's orientation. M Frictionless surface Hanging block H Q OK. Now how do I apply Fnet = ma to the sliding b Represent block S as a particle of mass M and dr the forces that act on it, as in Fig. 5-14a. This is the b free-body diagram. Next, draw a set of axes. It makes Figure 5-12 A block S of mass M is connected to a block H of mass m by a cord that wraps over a pulley.
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