Based on the measured angles of the marble launcher, calculate the initial horizontal and vertical components of the marble’s velocity for each angle, assuming the velocity vector has the same magnitude as you calculated from Part I (18.54 m/s). angle 1: θ = 15° -->initial height 0.027m, horizontal distance 0.145m angle 2: θ = 45° -->initial height 0.027m, horizontal distance 0.209m angle 3: θ = 70° --> initial height 0.027m, horizontal distance 0.118m

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Based on the measured angles of the marble launcher, calculate the initial horizontal and vertical components of the marble’s velocity for each angle, assuming the velocity vector has the same magnitude as you calculated from Part I (18.54 m/s).

angle 1: θ = 15° -->initial height 0.027m, horizontal distance 0.145m

angle 2: θ = 45° -->initial height 0.027m, horizontal distance 0.209m

angle 3: θ = 70° --> initial height 0.027m, horizontal distance 0.118m

 

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