In random, independent samples of 200 adults and 300 teenagers who watched a certain television show, 124 adults and 153 teens indicated that they liked the show. Let p, be the proportion of all adults watching the show who liked it, and let p, be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for p,-p,. Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least three decimal places. (If necessary, consult a list of formulas.) Lower limit: ? Upper limit:

In random, independent samples of 200 adults and 300 teenagers who watched a certain television show, 124 adults and 153 teens indicated that they liked the show. Let p, be the proportion of all adults watching the show who liked it, and let p, be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for p,-p,. Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least three decimal places. (If necessary, consult a list of formulas.) Lower limit: ? Upper limit:

Name: In random, independent samples of 200 adults and 300 teenagers who wa
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: In random, independent samples of 200 adults and 300 teenagers who watched a certain television show, 124 adults and 153 teens indicated that they liked theshow. Let p, be the proportion of all adults watching the show who liked it, and let p, be th

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: during production of detergent. In people with no lung dysfunction, a typical air flow rate is 0.80.…

A: As the population standard devoation is known, we will use z distribution. The value of z at the…

Q: Each student drew a simple random sample of fifty students and created a 99% condfidence interval…

A: It is given that student has drawn a simple random sample of fifty students and created a 99%…

Q: A survey found that 73% of a random sample of 8344 American adults approved of cloning endangering…

Q: A student in PSYC 227 class collects data for a class project. She asks 10 classmates to shoot 10…

A: The test is to check whether the variables X and Y are related or not.

Q: A survey of 425 randomly selected students at one university found that 300 students think they…

Q: A recent survey of size 1400 revealed that 29.4 percent of the people listen to Spotify as their…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120 significance level =…

Q: A man who moves to a new city sees that there are two routes he could take to work. A neighbor who…

A: Given Information: Route A: Sample size nA=15 Sample mean x¯A=46 Sample standard deviation sA=4…

Q: he lower end of the 95% confidence interval is Question Blank 1 of 2and the higher end of the 95%…

A: n=8 Sample sizex= 9.8 Sample mean s= 0.4 Sample standard deviation

Q: A man who moves to a new city sees that there are two routes he could take to work. A neighbor who…

A: Given X-bar-A=43 X-bar-B=48

Q: A mid-sized accounting firm is sending one of their auditors out to a client in the morning just in…

A: Given Information: Average time (u) = 130 minutes Standard deviation (s) = 30 minutes Target value…

Q: A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH…

A: In this context, it is given that The prediction interval for the pH of a glass of milk whose…

Q: The Baldwin Piano Company has long argued that their method of teaching people to play the piano is…

A: a) let the mean time of learning piano box Baldwin company is μ1the mean time of learning piano box…

Q: A survey of 100 customers showed that 36 of them preferred brand B of a particular product. Give a…

A: p = proportion of people vote for BSample size : n = 100Number of favorable outcomes : x =…

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: A man who moves to a new city sees that there are two routes he could take to work. A neighbor who…

Q: (b) A good way to judge the effect of outliers is to do your analysis twice, once With the sutilers…

A: The confidence interval for all data is, confidence interval =x¯ ± tα/2,n-1*S/nWhere, x¯…

Q: A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…

A: Given A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…

Q: A motorcycle dealer with the "Hd" brand wants to know the percentage of students in the city "X" who…

A: We have to find confidence interval.

Q: In a sample of 85 statistics students, 41 said that finding confidence intervals for population…

A: It is given that x is 41 and sample size (n) is 85. The confidence level is 0.99.

Q: 1. For each of the following confidence intervals for B,, (i) determine whether there is a linear…

Q: A researcher wanted to compare the percentages of men and women who play the lottery. They randomly…

Q: There is a new drug that reduces the body’s production of new blood vessels, thus starving the…

A: Given data: Margin of error = 0.03 Confidence level = 95% n = 23 x = 17

Q: A recent study by the McGraw-Hill company showed that 61% (1621) of college students use their…

A: Given, Proportion of college students use their smartphones for study = 0.61Total number of students…

Q: Suppose a researcher wants to test if the average diastolic blood pressure in Irish-Americans is…

A: It is given that the average diastolic blood pressure in the general population is 70 mmHg.…

Q: 10q3r1 (4) Body weight Bench press 148 145 176 148 154 133 189 156 181 166 217 174 210 168 150 139…

A: Given dataEnter the data in excel as shown below

Topic Video

Question

100%

In random, independent samples of 200 adults and 300 teenagers who watched a certain television show, 124 adults and 153 teens indicated that they liked the
show. Let p, be the proportion of all adults watching the show who liked it, and let p, be the proportion of all teens watching the show who liked it. Find a 90%
confidence interval for p,-p,. Then find the lower limit and upper limit of the 90% confidence interval.
Carry your intermediate computations to at least three decimal places. Round your responses to at least three decimal places. (If necessary, consult a list of
formulas.)
Lower limit:
Upper limit:
O O

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <
Of the 250 students surveyerd, 100 prefered asynchronous distance learning and 150 prefered synchronous distance learning. construct a 95% confidence interval for the proportion of stuednts who prefer asynchronous distance learning.
A random sample of 500 males included 215 that approved of the performance of a President. A random sample of 500 females included 185 that approved of the performance of a President. Determine each of the following parts that will lead you to construct a 95% confidence interval for the overall difference in the percentage of males and females that approve of the President's performance. group one males, gorup 2 females Calculate E, the margin of error, for a 95% level of confidence, Create the final confidence interval for the difference in percentages
Alfredo wants a 85% confidence interval for the true average gas mileage for a Gremlin after randomly sampling 9 Gremlins. It is known that the true sigma for Gremlin gas mileage is 4 mpg, and the average of the 9 Gremlins in Alfredo's study was 24 mpg. Find the confidence interval assuming the distribution is normal.
2. An experiment showed that 52 teenage subjects dreamed in black and white & 175 of them dreamed in colors. Another study on old-age adults showed that 5 dreamed in black and white & 40 of them dreamed in colors. Find the 95% confidence interval for the difference between the rates who dreamed in black and white and those in colors. please show how to solve it. no excel please.
A set of 11 data pairs (x.y) were collected and were found to have a linear relationship given by: y = 3.04 x + 0.99 The Standard Error of the Fit for this equation is 0.755 and the confidence interval, CI, is written as: y = ax + b+ (e) Provide the value of the margin of error, e, at a confidence level of 95%. (Use 3 decimal places to express your answer).
A random sample of 34 chemists from Washington state shows an average salary of $41857, the population standard deviation for chemist salaries in Washington state is $697. A random sample of 35 chemists from Florida state shows an average salary of $44632, the population standard deviation for chemist salaries in Florida state is $900. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.05 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: Ο Ηο: μι μ2(claim) Ο Ηο: μι 2 με HAM12(claim) Ho: M₁ = H2 1 HAM12(claim) Since the level of significance is 0.05 the critical value is 1.96 and -1.96 The test statistic is: (round to 3 places) The p-value is: (round to 3 places)
A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time tells him Route A will average 5 minutes faster than Route B. The man decides to experiment. Each day he flips a coin to determine which way to go, driving each route 20 days. He finds that Route A takes an average of 45 minutes, with standard deviation 3 minutes, and Route B takes an average of 49 minutes, with standard deviation 5 minutes. Histograms of travel times for the routes are roughly symmetric and show no outliers. Complete parts a and b. (...) a) Find a 95% confidence interval for the difference between the Route B and Route A commuting times, (µÂ ¯ µÃ) - The confidence interval is (.). (Round to two decimal places as needed.)
A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
The number of books sold over the course of the for day book fair were 195, 158, 263 and 100. Assume that samples of size 2 are randomly selected with replacement from this population of four values. List the different possible samples and find the mean of each of them.
In a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places