In Quantum Mechanics, even if E < U, there is a chance that the particle might tunnel through it. This concept is different from the classical mechanics. True or false
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A: Option D is correct
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A: We will answer this question by looking at definition of linear operator.
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Q: V (x) = 00, V(r) = 0. x<0,x 2 a %3D 0<x< a
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Q: 2. A free particle (a particle that has zero potential energy) has mass 8 eV/c² and total energy 10…
A: Given m = 8ev/c2 E = 10 ev V = 5 ev To find- the first three subparts above
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- Suppose we had a classical particle in a frictionless box, bouncing back and forth at constant speed. The probability density of the position of the particle in soma box of length L is given by: 0 ans-fawr (7) p(x)= 0 x L a. Sketch the probability density as a function of position b. What must A be in order for p(x) to be normalized? Remember that you are welcome to use resources to solve integrals such as Wolfram Alpha, a table of integrals etc.5. Consider a potential barrier represented as follows: U M 0 +a U(x) = x a Determine the transmission coefficient as a function of particle energy.A 4.90g Particle confined to a box of length L has a speed of 4.70mm/s a) lalhat is the classical Kinetic energy of Particle? the b) If the energy of the first excited State (n=2) is equal to the Kinetic energy found in part (a), what is the value Note: Answer must be in mi L? of c) Is the result found in part (b) realistic ? Explain.
- Suppose a 1D quantum system is represented by the wavefunction in position space: (æ|2>(t)) = b(x, t) = Ae -3x+5it where it only exists () < x < ! Normalize the wavefunction, i.e., what is A?A particle of mass m is moving in one-dimension in a potential V (x) with zero energy. The wave function for the particle is Þ(x) = Axe-x²/a? Where A and a are constants a) Use Schrodinger equation to find the potential energy V (x) of the particle. b) Evaluate your answer at x = 0(d) Prove that for a classical particle moving from left to right in a box with constant speed v, the average position = (1/T) ff x(t) dt = L/2, where T L/v is the time taken to move from left to right. And = : (1/T) S²x² (t) dt L²/3. Hint: Only consider a particle moving from left x = 0 to right x = L = and do not include the bouncing motion from right to left. The results for left to right are independent of the sense of motion and therefore the same results apply to all the bounces, so that we can prove it for just one sense of motion. Thus, the classical result is obtained from the Quantum solution when n >> 1. That is, for large energies compared to the minimum energy of the wave-particle system. This is usually referred to as the Classical Limit for Large Quantum Numbers.