In python, the function countWordsOfLength takes a list of words L and an integer n, and returns the total number of words of length n that appear in the list. For example, countWordsOfLength(["yes", "no", "maybe", "NNOOO"], 5)would return 2 because the given list has two words of length 5. Hint: Use the accumulator pattern to solve this problem. Inside the for loop, use an if statement to only update the accumulator when the current word has length n. Hint: Instead of using a for loop with a range, you can iterate directly over  the elements of L. For example: Test Result L = ['a', 'b', 'c', 'de', 'fgh', 'i', 'jkl'] print(countWordsOfLength(L, 1)) 4 L = ['a', 'b', 'c', 'de', 'fgh', 'i', 'jkl'] print(countWordsOfLength(L, 5)) 0 L = ['bacon', 'onion', 'pepper', 'garlic', 'paprika', 'chipotle chili powder', 'salt', 'black pepper', 'vinegar', 'bbq sauce', 'ketchup', 'mustard', 'brown sugar', 'beans'] print(countWordsOfLength(L, 5)) 3

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