In Python , I need the first and second answer **Function Description: max(L)**Write a function `max(L)` which examines the argument list `L`, and returns the largest object of type float. If there is no float object in the list, then the function returns `None`. **Examples:**- `max([100, 'blue', 3.5, 'sugar on the rocks', 7.0])` would return `7.0`- `max([7, 2, 9, 1])` would return `None`**Note:**- `type(element) == float` is a way to check if `element` is a float. **Exercise 6: Calculating the Perimeter of a Polygon**Objective: Write a function named `perimeter(poly)` that calculates the perimeter of a polygon. The input, `poly`, should be a list of tuples. Each tuple represents the (x, y) coordinates of a point on the polygon. The perimeter is determined by summing the distances between consecutive points, including the distance from the last point back to the first point.**Formula for Distance Calculation:**For two points, \((x_1, y_1)\) and \((x_2, y_2)\), the distance is given by:\[ \text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]**Instructions:**1. Test your function with simple shapes such as a square, a rectangle, and a triangle, where the expected results are known.2. To perform square root calculations, import the `math` module and use `math.sqrt`.Example Implementation in Python:```pythonimport mathdef perimeter(poly): total_distance = 0 # Loop through each point in the polygon for i in range(len(poly)): x1, y1 = poly[i] x2, y2 = poly[(i + 1) % len(poly)] # Connect last point to first total_distance += math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2) return total_distance```**Practice:**Test this function on a variety of polygons to ensure accuracy and reliability of your implementation. Consider edge cases such as degenerate polygons and ensure that your function handles them appropriately.

In the first question, we have to find the maximum float element of the list.In the second question,…

2. Write a function max(L) which examines the argument list L, and returns the largest object of ty float. If there is no float object in the list, then the function returns None. For example, max([100, 'blue', 3.5, 'sugar on the rocks', 7.0]) would retûrn 7.0, and max([7, 2, 9, 1]) would return None. Note that type(element) == float is a way to check if element is a float.

2. Write a function max(L) which examines the argument list L, and returns the largest object of ty float. If there is no float object in the list, then the function returns None. For example, max([100, 'blue', 3.5, 'sugar on the rocks', 7.0]) would retûrn 7.0, and max([7, 2, 9, 1]) would return None. Note that type(element) == float is a way to check if element is a float.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

In Python , I need the first and second answer

**Function Description: max(L)**

Write a function `max(L)` which examines the argument list `L`, and returns the largest object of type float. If there is no float object in the list, then the function returns `None`.

**Examples:**

- `max([100, 'blue', 3.5, 'sugar on the rocks', 7.0])` would return `7.0`
- `max([7, 2, 9, 1])` would return `None`

**Note:**

- `type(element) == float` is a way to check if `element` is a float.

**Exercise 6: Calculating the Perimeter of a Polygon**

Objective: Write a function named `perimeter(poly)` that calculates the perimeter of a polygon. The input, `poly`, should be a list of tuples. Each tuple represents the (x, y) coordinates of a point on the polygon. The perimeter is determined by summing the distances between consecutive points, including the distance from the last point back to the first point.

**Formula for Distance Calculation:**

For two points, \((x_1, y_1)\) and \((x_2, y_2)\), the distance is given by:

\[ \text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

**Instructions:**

1. Test your function with simple shapes such as a square, a rectangle, and a triangle, where the expected results are known.
2. To perform square root calculations, import the `math` module and use `math.sqrt`.

Example Implementation in Python:

```python
import math

def perimeter(poly):
total_distance = 0

# Loop through each point in the polygon
for i in range(len(poly)):
x1, y1 = poly[i]
x2, y2 = poly[(i + 1) % len(poly)] # Connect last point to first
total_distance += math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)

return total_distance
```

**Practice:**

Test this function on a variety of polygons to ensure accuracy and reliability of your implementation. Consider edge cases such as degenerate polygons and ensure that your function handles them appropriately.

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