In program problem5.py, write a function named sums that takes 3 arguments: 2 lists of integers nums1 and nums 2, and an integer target; then return a tuple containing indices i and j of the two numbers in nums I and nums 2, respectively, where the numbers at that indices add up to target (i.e, nums1 [i] + num2[j] = target). If there is no solution, return "Not found". The function sums must contain exactly only one loop (either a for-loop or a while-loop), otherwise you will get no point. A nested-loop is considered as more than one loop. You can assume that each given input either have exactly one solution or none. Below is the code of the main function in problem5.py, complete the program by writing the function sums. Note that the values of nums 1, nums2 and target are given in the main function which can be changed in the code. This program does not take any input. if name __main____: nums1 = [11, 2, 15, 7, 8] nums2 = [3, 4, 5] target=9 print(sums(nums 1, nums2, target)) Example 1: Input nums1 = [11, 2, 15, 7, 8], nums2 = [2, 3, 4, 5], target=9 Output (3, 0) Explanation: Because nums 1[3] + nums2[0] == 9, we return (3, 0). Example 2: Input nums1 = [11, 2, 15, 7, 8], nums2 = [3, 4, 5], target=9 Output Not found
In program problem5.py, write a function named sums that takes 3 arguments: 2 lists of integers nums1 and nums 2, and an integer target; then return a tuple containing indices i and j of the two numbers in nums I and nums 2, respectively, where the numbers at that indices add up to target (i.e, nums1 [i] + num2[j] = target). If there is no solution, return "Not found". The function sums must contain exactly only one loop (either a for-loop or a while-loop), otherwise you will get no point. A nested-loop is considered as more than one loop. You can assume that each given input either have exactly one solution or none. Below is the code of the main function in problem5.py, complete the program by writing the function sums. Note that the values of nums 1, nums2 and target are given in the main function which can be changed in the code. This program does not take any input. if name __main____: nums1 = [11, 2, 15, 7, 8] nums2 = [3, 4, 5] target=9 print(sums(nums 1, nums2, target)) Example 1: Input nums1 = [11, 2, 15, 7, 8], nums2 = [2, 3, 4, 5], target=9 Output (3, 0) Explanation: Because nums 1[3] + nums2[0] == 9, we return (3, 0). Example 2: Input nums1 = [11, 2, 15, 7, 8], nums2 = [3, 4, 5], target=9 Output Not found
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![In program problem5.py, write a function named sums that takes 3 arguments: 2 lists of integers
nums1 and nums 2, and an integer target; then return a tuple containing indices i and j of the two
numbers in nums 1 and nums 2, respectively, where the numbers at that indices add up to target (i.e,
nums1 [i] + num2[j] = target). If there is no solution, return "Not found". The function sums must
contain exactly only one loop (either a for-loop or a while-loop), otherwise you will get no point.
A nested-loop is considered as more than one loop.
You can assume that each given input either have exactly one solution or none.
Below is the code of the main function in problem5.py, complete the program by writing the
function sums. Note that the values of nums 1, nums2 and target are given in the main function
which can be changed in the code. This program does not take any input.
if name
__main__':
nums1 = [11, 2, 15, 7, 8]
nums2 = [3, 4, 5]
target = 9
print(sums(nums 1, nums2, target))
Example 1:
Input
nums 1 = [11, 2, 15, 7, 8], nums2 = [2, 3, 4, 5], target = 9
Output
(3, 0)
Explanation: Because nums 1[3] + nums2[0] == 9, we return (3, 0).
Example 2:
Input
nums1 = [11, 2, 15, 7, 8], nums2 = [3, 4, 5], target = 9
Output
Not found](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ef01312-e661-404d-b21d-a0691da0b882%2Fd802f49d-d00c-4588-a5a4-4f8e89dd8231%2Fovg1vr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In program problem5.py, write a function named sums that takes 3 arguments: 2 lists of integers
nums1 and nums 2, and an integer target; then return a tuple containing indices i and j of the two
numbers in nums 1 and nums 2, respectively, where the numbers at that indices add up to target (i.e,
nums1 [i] + num2[j] = target). If there is no solution, return "Not found". The function sums must
contain exactly only one loop (either a for-loop or a while-loop), otherwise you will get no point.
A nested-loop is considered as more than one loop.
You can assume that each given input either have exactly one solution or none.
Below is the code of the main function in problem5.py, complete the program by writing the
function sums. Note that the values of nums 1, nums2 and target are given in the main function
which can be changed in the code. This program does not take any input.
if name
__main__':
nums1 = [11, 2, 15, 7, 8]
nums2 = [3, 4, 5]
target = 9
print(sums(nums 1, nums2, target))
Example 1:
Input
nums 1 = [11, 2, 15, 7, 8], nums2 = [2, 3, 4, 5], target = 9
Output
(3, 0)
Explanation: Because nums 1[3] + nums2[0] == 9, we return (3, 0).
Example 2:
Input
nums1 = [11, 2, 15, 7, 8], nums2 = [3, 4, 5], target = 9
Output
Not found
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