In standard C programming esc6.19 LAB: Adjust list by normalizingWhen analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done bynormalizing to values between 0 and 1, or throwing away outliers.For this program, adjust the values by dividing all values by the largest value. The input begins with an integer indicating the number offloating-point values that follow. Assume that the list will always contain less than 20 floating-point values.For coding simplicity, follow every output value by a space, including the last one. And, output each floating-point value with two digits afterthe decimal point, which can be achieved as follows:printf("80.21f ", yourValue);Ex: If the input is:5 30.0 50.0 10.0 100.0 65.0the output is:0.30 0.50 0.10 1.00 0.65The 5 indicates that there are five floating-point values in the list, namely 30.0, 50.0, 10.0, 100.0, and 65.0. 100.0 is the largest value in thelist, so each value is divided by 100.0.For coding simplicity, follow every output value by a space, including the last one.427864 2734514.qx3zqy7LABACTIVITY1 #include 23 int main(void) {456.19.1: LAB: Adjust list by normalizing6/* Type your code here. */806main.c4▶II890/10Load default template...G

C program: #include <stdio.h> int main(void) //Program execution starts from here{ int n; float a[20]; printf("Enter number of values: "); //Asking user to enternumber of values scanf("%d",&n); printf("Enter values: "); //Asking user to enter values for(int i=0;i<n;i++){ scanf("%f",&a[i]); } float max=a[0]; //Finding maximum values for(int i=0;i<n;i++){ if(a[i]>=max){ max=a[i]; } } for(int i=0;i<n;i++){ //Dividing each values by maximum value printf("%0.2lf ",a[i]/max); } return 0;}Output: