In preparing a drug design, it is determined that the drug will work better if a molecule of NaCl can be dissociate to free ions in the plasma membrane of a cell. Is this plan feasible? O No, the energy needed to dissociate is too high in the plasma membrane. Yes, because there are special proteins in the plasma membrane that specifically break NaCl into free ions. O No, even though NaCl would freely dissociate the ions would be lost. Yes, because the plasma membrane is an aqueous solution there is no problem.

In preparing a drug design, it is determined that the drug will work better if a molecule of NaCl can be dissociate to free ions in the plasma membrane of a cell. Is this plan feasible? O No, the energy needed to dissociate is too high in the plasma membrane. Yes, because there are special proteins in the plasma membrane that specifically break NaCl into free ions. O No, even though NaCl would freely dissociate the ions would be lost. Yes, because the plasma membrane is an aqueous solution there is no problem.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the bases row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCH,CO, is a weak acid. acids D 15 mot of NaOH is added to 1.0 L of a 1,5 M HCH,CO,Coses: 0 solution Dother D 0 0.1 mat of HI is added to 1.0 L of a sution that is 0.4M in both HCH, CO, and NaCH, CO₂ adds: DOO bases D Der D Doan 5 (20 M
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 0.2 mol of KOH is added to 1.0 L of a 0.5 M HF bases: | solution. other: O acids: 0.1 mol of NAOH is added to 1.0 L of a solution that is bases: | 0.4 M in both HF and NaF. other: O
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 1.4 mol of NaOH is added to 1.0 L of a 1.4M HF solution. bases: ☐ ☑ other: ☐ acids: 0.3 mol of NaOH is added to 1.0 L of a solution that is bases: ☐ 0.7M in both HF and KF. other: ☐
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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that NH3 is a weak base. 0.26 mol of HCl is added to 1.0L of a 1.2M NH3 solution. acids: bases: other: 0.06 mol of HBr is added to 1.0Lof a solution that is 0.2M in both NH3 and NH4Cl. acids: bases: other:
Please answer question 20 Part A