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In Peter Jackson's adaptation of The Two Towers, the wizard Gandalf falls from the Bridge of Khazad-dûm for a total screen time of 71 seconds. Darren wanted to calculate the maximum height the fall could have been and running the numbers concluded that it could be at most 4.94 km from the bridge to the heart of the mountain below. Is Darren's conclusion a fair estimation of the total

In Peter Jackson's adaptation of The Two Towers, the wizard Gandalf falls from the Bridge of Khazad-dûm for a total screen time of 71 seconds. Darren wanted to calculate the maximum height the fall could have been and running the numbers concluded that it could be at most 4.94 km from the bridge to the heart of the mountain below. Is Darren's conclusion a fair estimation of the total

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In Peter Jackson's adaptation of The Two Towers, the wizard Gandalf falls from the Bridge of Khazad-dûm for a total screen time of 71 seconds. Darren wanted to calculate the maximum height the fall could have been and running the numbers concluded that it could be at most 4.94 km from the bridge to the heart of the mountain below.

Is Darren's conclusion a fair estimation of the total fall distance?

Be sure to:
*State your claim of agreeing or disagreeing with 4.94 km being a reasonable height for the fall. 
*Gather evidence from your own calculations, observations from the film.
*Connect your evidence to your claim by reasoning why it supports your claim. Any evidence you share should be directly linked with your reasoning to why or why not 4.94 km is a reasonable estimate for the falling distance. Include your calculations.

Givens 

X= 

t=

Vi=

Vf=

a=g=-9.8 m/s^2

 

Use the Equation:

x=vit+1/2at^2

 

 

Falling down How fardid something fall if it takes 5 seconds from drop to hitting the ground? g X = V₁t + ½ at ² E Givens: x= wast t = 5 s V;= 0 m/s ? Vf= a=g -१.४ misa X = ág t² < × = 1/2 (-99) (5²) X X = 121.5m To get started, you really need 3/5 variables to get started this is the model equation for dropped objects (v₁ - v₁) t V₁ = V₁ + at v² = v7 + 2ax 1 x = v₁t + = at² (0₁ + 2 ) c
Transcribed Image Text:Falling down How fardid something fall if it takes 5 seconds from drop to hitting the ground? g X = V₁t + ½ at ² E Givens: x= wast t = 5 s V;= 0 m/s ? Vf= a=g -१.४ misa X = ág t² < × = 1/2 (-99) (5²) X X = 121.5m To get started, you really need 3/5 variables to get started this is the model equation for dropped objects (v₁ - v₁) t V₁ = V₁ + at v² = v7 + 2ax 1 x = v₁t + = at² (0₁ + 2 ) c
Claim Evidence. Reasoning The train will NOT stop in time. m/s² and only has 300 meters to stop Will it stop in time? Givens: $2,101,8 v₁ = 60 p/s a=-3° 1 0² = 50² +2(a)x 9560 -4* *42 1x 2000 H With the given values, the evidence of the calculation of the stopping distance was found to be 625m. That is greater than the 300m of the car's location, so the train can not stop in time.
Transcribed Image Text:Claim Evidence. Reasoning The train will NOT stop in time. m/s² and only has 300 meters to stop Will it stop in time? Givens: $2,101,8 v₁ = 60 p/s a=-3° 1 0² = 50² +2(a)x 9560 -4* *42 1x 2000 H With the given values, the evidence of the calculation of the stopping distance was found to be 625m. That is greater than the 300m of the car's location, so the train can not stop in time.
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