Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
In parallelogram DEFG, what is the EY?
![In the given problem, we have a parallelogram, DEFG, with diagonals that intersect at point Y. The problem asks to find the length of EY.
The diagram is a kite-shaped four-sided figure with the following details:
1. **DG and EF are diagonals:**
- DG = 5x - 5
- EF = 3x + 9
- DY = 4x - 3
2. **Diagonals bisect each other at point Y:**
- In parallelograms, diagonals bisect each other equally. Therefore, DY = YE and GY = YF.
3. **Equations for the line segments:**
- If DY = 4x - 3, then YE should also equal 4x - 3.
To find the values:
1. **Set the segments of equal length:** Since diagonals bisect each other,
\( DG = EF \)
\((5x - 5) + (3x + 9) = 2(4x - 3)\).
2. **Solve for x:**
- Equate the expressions for the diagonals:
\[ 5x - 5 = 4x - 3 \]
- Solve for x:
\[ 5x - 4x = -3 + 5 \]
\[ x = 2 \]
3. **Find EY:**
- Substitute x in DY = 4x - 3:
\[ EY = 4(2) - 3 \]
\[ EY = 8 - 3 \]
\[ EY = 5 \]
Therefore, x = 2 and EY = 5.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c2913e4-3d86-4c39-9afb-ae3f41846d68%2F246caf91-818f-41f8-b2ab-1666e118ed0f%2F1tw7cw_processed.png&w=3840&q=75)
Transcribed Image Text:In the given problem, we have a parallelogram, DEFG, with diagonals that intersect at point Y. The problem asks to find the length of EY.
The diagram is a kite-shaped four-sided figure with the following details:
1. **DG and EF are diagonals:**
- DG = 5x - 5
- EF = 3x + 9
- DY = 4x - 3
2. **Diagonals bisect each other at point Y:**
- In parallelograms, diagonals bisect each other equally. Therefore, DY = YE and GY = YF.
3. **Equations for the line segments:**
- If DY = 4x - 3, then YE should also equal 4x - 3.
To find the values:
1. **Set the segments of equal length:** Since diagonals bisect each other,
\( DG = EF \)
\((5x - 5) + (3x + 9) = 2(4x - 3)\).
2. **Solve for x:**
- Equate the expressions for the diagonals:
\[ 5x - 5 = 4x - 3 \]
- Solve for x:
\[ 5x - 4x = -3 + 5 \]
\[ x = 2 \]
3. **Find EY:**
- Substitute x in DY = 4x - 3:
\[ EY = 4(2) - 3 \]
\[ EY = 8 - 3 \]
\[ EY = 5 \]
Therefore, x = 2 and EY = 5.
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