In order to pass a physical education class at a university, a student must run 1.0 mi in 11.5 min. After running for 10.0 min (assume constant speed), she still has 660 yd to go. What constant acceleration does she need over the final 660 yd in order to make it? (Note: 1 yard is equal to 0.9144 meters.) m/s2
In order to pass a physical education class at a university, a student must run 1.0 mi in 11.5 min. After running for 10.0 min (assume constant speed), she still has 660 yd to go. What constant acceleration does she need over the final 660 yd in order to make it? (Note: 1 yard is equal to 0.9144 meters.) m/s2
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In order to pass a physical education class at a university, a student must run 1.0 mi in 11.5 min. After running for 10.0 min (assume constant speed), she still has 660 yd to go. What constant acceleration does she need over the final 660 yd in order to make it? (Note: 1 yard is equal to 0.9144 meters.)
m/s2
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1: To calculate initial velocity
To calculate initial velocity which is maintained for 10 min-
u=st where (u is initial velocity, s is distance and t is time)
Firstly let us make each unit in meters and seconds-
1.0 mi=1609.344m
660 yards= 603.504 m
10min=600 sec
now,
u=change in distance time
u= (1609.344-603.504)600=1.68 m/s
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