In order to pass a physical education class at a university, a student must run 1.0 mi in 11.5 min. After running for 10.0 min (assume constant speed), she still has 660 yd to go. What constant acceleration does she need over the final 660 yd in order to make it? (Note: 1 yard is equal to 0.9144 meters.) m/s2

In order to pass a physical education class at a university, a student must run 1.0 mi in 11.5 min. After running for 10.0 min (assume constant speed), she still has 660 yd to go. What constant acceleration does she need over the final 660 yd in order to make it? (Note: 1 yard is equal to 0.9144 meters.) m/s2

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 64AP: To pass a physical education class at a university, a student must run 1.0 mi in 12 min. After...

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Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

m/s²

Expert Solution

Step 1: To calculate initial velocity

To calculate initial velocity which is maintained for 10 min-

u=s $\div$ t where (u is initial velocity, s is distance and t is time)

Firstly let us make each unit in meters and seconds-

1.0 mi=1609.344m

660 yards= 603.504 m

10min=600 sec

now,

u=change in distance $\div$ time

u= (1609.344-603.504) $\div$ 600=1.68 m/s

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