In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3. Ksp= 1.57x10^-9 How many millimoles of Ba(NO3)2 are there in the solution? 250 mmol 125 mmol 50 mmol2 5 mmol How many millimoles of NaIO3 are there in the solution? 250 mmol 125 mmol 50 mmol 25 mmol
In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3. Ksp= 1.57x10^-9 How many millimoles of Ba(NO3)2 are there in the solution? 250 mmol 125 mmol 50 mmol2 5 mmol How many millimoles of NaIO3 are there in the solution? 250 mmol 125 mmol 50 mmol 25 mmol
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability
Section: Chapter Questions
Problem 41PS
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In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3.
Ksp= 1.57x10^-9
How many millimoles of Ba(NO3)2 are there in the solution?
- 250 mmol
- 125 mmol
- 50 mmol2
- 5 mmol
How many millimoles of NaIO3 are there in the solution?
- 250 mmol
- 125 mmol
- 50 mmol
- 25 mmol
How many millimoles of NaIO3 are needed to completely react with the Ba(NO3)2?
- 500 mmol
- 250 mmol
- 25 mmol
- 12.5 mmol
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