In one half-cell of a galvanic cell, a piece of platinum metal, Pt, dips into a solution containing 0.850 M Fe * and 0.010M Fe ". In the other half-cell a piece of cadmium metal, Cd, dips into a 0.500 M solution of Cd 2*. a. g° = +0.771 V for Fe * + e 2 Fe 2* g° = -0.403 V for Cd 2* + 2 e 2 cd i. Write the shorthand notation for the cell. i. Calculate the standard cell potential, e°. iii. Calculate the equilibrium constant for the cell reaction. 1.

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Chapter1: Chemical Foundations
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1. a.
In one half-cell of a galvanic cell, a piece of platinum metal, Pt, dips into a
solution containing 0.850 M Fe * and 0.010M Fe 2*. In the other half-cell a piece
of cadmium metal, Cd, dips into a 0.500 M solution of Cd 2*.
€° = +0.771 V for Fe * +
e 2 Fe *
e° = -0.403 V for Cd 2* + 2 e 2 cd
i.
Write the shorthand notation for the cell.
ii.
Calculate the standard cell potential, ɛ°.
ii.
Calculate the equilibrium constant for the cell reaction.
iv.
Calculate the cell potential, ɛ.
b.
The oxidation of ethanol by the permanganate ion, MnO, in aqueous acidic
solution produces ethanoic acid and Mn²*. Use the half reaction method and
write the balanced equation for this reaction.
Transcribed Image Text:1. a. In one half-cell of a galvanic cell, a piece of platinum metal, Pt, dips into a solution containing 0.850 M Fe * and 0.010M Fe 2*. In the other half-cell a piece of cadmium metal, Cd, dips into a 0.500 M solution of Cd 2*. €° = +0.771 V for Fe * + e 2 Fe * e° = -0.403 V for Cd 2* + 2 e 2 cd i. Write the shorthand notation for the cell. ii. Calculate the standard cell potential, ɛ°. ii. Calculate the equilibrium constant for the cell reaction. iv. Calculate the cell potential, ɛ. b. The oxidation of ethanol by the permanganate ion, MnO, in aqueous acidic solution produces ethanoic acid and Mn²*. Use the half reaction method and write the balanced equation for this reaction.
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