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In one experiment, 12.0 g of PCl5 was slowly added to 15.0 g of H2O according to the following balanced chemical equation: Pcl5(s)+4H2O(l) ---> H3PO4 (aq) + 5HCl (g) The molar masses for each compound in the equation are as follows;  PCl5: 208.224 g/mol H2O: 18.015 g/mol H3PO4: 97.994 g/mol HCl; 36.45 g/mol   Based on the information above and the information attached explain in WORDS why PCl5 is the limiting reagent.

In one experiment, 12.0 g of PCl5 was slowly added to 15.0 g of H2O according to the following balanced chemical equation: Pcl5(s)+4H2O(l) ---> H3PO4 (aq) + 5HCl (g) The molar masses for each compound in the equation are as follows;  PCl5: 208.224 g/mol H2O: 18.015 g/mol H3PO4: 97.994 g/mol HCl; 36.45 g/mol   Based on the information above and the information attached explain in WORDS why PCl5 is the limiting reagent.

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ISBN:9781305957404
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In one experiment, 12.0 g of PCl5 was slowly added to 15.0 g of H2O according to the following balanced chemical equation:

Pcl5(s)+4H2O(l) ---> H3PO4 (aq) + 5HCl (g)

The molar masses for each compound in the equation are as follows; 

PCl5: 208.224 g/mol

H2O: 18.015 g/mol

H3PO4: 97.994 g/mol

HCl; 36.45 g/mol

 

Based on the information above and the information attached explain in WORDS why PCl5 is the limiting reagent.

limiting reactant the reactant that restricts the extent to which a chemical reaction will occur the reactant amount used to predict the maximum amount of product which will form may or may not be "leftover" excess reactant the reactant(s) in a chemical process that is included in an amount that is more than necessary
Transcribed Image Text:limiting reactant the reactant that restricts the extent to which a chemical reaction will occur the reactant amount used to predict the maximum amount of product which will form may or may not be "leftover" excess reactant the reactant(s) in a chemical process that is included in an amount that is more than necessary
2:38 Number of moles of a compound is calculated by the ratio between the mass of the compound to its molar mass. Number of moles of PCl5= Step3 c) Number of moles of H₂O=. Mass of PC15 Molar mass of PC15 12.0 g 208.244 g/mol -0.0576 mol .LTE 45 ? Mass of H₂O Molar mass of H₂O 15.0 g 18.015 g/mol =0.8326 mol Limiting reagent can be determined by the balanced reaction and unitary method. of moles of water=4 mol of moles of water=0.0576 mol PCl5 × =0.2304 mol water However, the number of moles of water are 0.8326 mol. So PC15 will be completely consumed during the reaction and will be the limiting reagents of the reaction. Step4 d) PC15 will be the limiting reagent of the reaction. √x 4 mol water 1 mol PCl5 Do
Transcribed Image Text:2:38 Number of moles of a compound is calculated by the ratio between the mass of the compound to its molar mass. Number of moles of PCl5= Step3 c) Number of moles of H₂O=. Mass of PC15 Molar mass of PC15 12.0 g 208.244 g/mol -0.0576 mol .LTE 45 ? Mass of H₂O Molar mass of H₂O 15.0 g 18.015 g/mol =0.8326 mol Limiting reagent can be determined by the balanced reaction and unitary method. of moles of water=4 mol of moles of water=0.0576 mol PCl5 × =0.2304 mol water However, the number of moles of water are 0.8326 mol. So PC15 will be completely consumed during the reaction and will be the limiting reagents of the reaction. Step4 d) PC15 will be the limiting reagent of the reaction. √x 4 mol water 1 mol PCl5 Do
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