In July of 2013, Australians were asked if they thought unemployment would increase, and 47% thought that it would increase. In November of 2013, they were asked again. At that time 306 out of 700 said that they thought unemployment would increase. At the 8% level, is there enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013?
In July of 2013, Australians were asked if they thought unemployment would increase, and 47% thought that it would increase. In November of 2013, they were asked again. At that time 306 out of 700 said that they thought unemployment would increase. At the 8% level, is there enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013?
P: PARAMETER
What is the correct parameter symbol for this problem?
What is the wording of the parameter in the context of this problem?
H: HYPOTHESES
Fill in the correct null and alternative hypotheses:
H0:H0:
HA:HA:
A: ASSUMPTIONS
Since information was collected from each object, what conditions do we need to check?
Check all that apply.
- n(1−p)≥10n(1-p)≥10
- n≥30n≥30 or normal population.
- σσ is known.
- n(pˆ)≥10n(p̂)≥10
- np≥10np≥10
- n(1−pˆ)≥10n(1-p̂)≥10
- σσ is unknown.
- N≥20nN≥20n
Check those assumptions:
1. npnp = which is
2. n(1−p)n(1-p) = which is
3. NN = which is
If no N is given in the problem, use 1000000
N: NAME THE PROCEDURE
The conditions are met to use a .
T: TEST STATISTIC
The symbol and value of the random variable on this problem are as follows:
Leave this answer as a fraction.
=
The formula set up of the test statistic is as follows.:
(Leave any values that were given as fractions as fractions)
z=pˆ−p√p(1−p)n=z=p̂-pp(1-p)n=
( −- )/√((/(( ⋅(1−⋅(1- )) // ))
Final answer for the test statistic from technology.
Round to 2 decimal places:
z =
O: OBTAIN THE P-VALUE
Report to 4 decimal places.
It is possible when rounded that a p-value is 0.0000
P-value =
M: MAKE A DECISION
Since the p-value , we .
S: STATE A CONCLUSION
There significant evidence to conclude
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