In his mission as a spy, Loid Forger fired a bullet weigh = 0.007 kg with a horizontal speed of vB= 550 m/s into lower end of a gate which can be modeled into a slend m=16-kg bar of length L=1.5m for simplified analysis o Know that h=0.25 m and that the gate, which has a pin connection at point C, is initially at rest. The bullet bec

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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In his mission as a spy, Loid Forger fired a bullet weighing mB
= 0.007 kg with a horizontal speed of VB= 550 m/s into the
lower end of a gate which can be modeled into a slender
m=16-kg bar of length L=1.5m for simplified analysis only.
Know that h=0.25 m and that the gate, which has a pin
connection at point C, is initially at rest. The bullet becomes
embedded into the gate after impact.
1.5 m
с
A
D
0.25 m
VB= 550 m/s
Transcribed Image Text:In his mission as a spy, Loid Forger fired a bullet weighing mB = 0.007 kg with a horizontal speed of VB= 550 m/s into the lower end of a gate which can be modeled into a slender m=16-kg bar of length L=1.5m for simplified analysis only. Know that h=0.25 m and that the gate, which has a pin connection at point C, is initially at rest. The bullet becomes embedded into the gate after impact. 1.5 m с A D 0.25 m VB= 550 m/s
2. Which of the following momentum equations about C is CORRECT and can be used to solve for
the angular velocity of the gate? ◆
A. 1.25mßvß = 1.25mßvß - 0.5mvg — ÏÅ Bw
B. 1.25m BVB = 1.25mßvß +0.5mvg + IA Bw
C. 1.250mßvß = 1.250mßvß +0.500mvG
D. 1.25mßvß = 1.25mBvB – 0.5mvG
Transcribed Image Text:2. Which of the following momentum equations about C is CORRECT and can be used to solve for the angular velocity of the gate? ◆ A. 1.25mßvß = 1.25mßvß - 0.5mvg — ÏÅ Bw B. 1.25m BVB = 1.25mßvß +0.5mvg + IA Bw C. 1.250mßvß = 1.250mßvß +0.500mvG D. 1.25mßvß = 1.25mBvB – 0.5mvG
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