Please have clear step by step processes.. I am having a hard time grasping the steps on this concept. Yp(z) = y1 (z) /Y2(z)f(z) dz + y2(z) / Vusing the method of variation of parameters isIn general for a non-homogeneous problem y" + p(z)y + g(z)y= f(z) assume that y1, 2 is a fundamental set of solutions for the homogeneous problem y" + p(zr)y' + g(z)y = 0. Then the formula for the particular solutionYp = Y141 +F y2u2-y2(z) f(x)W(z)Y1 (z)f(z)W(z)where u =and u =where W(z) is the Wronskian given by the determinant|31 (2) 2(z)||3{(z) %½(z)|W(z) =* 1 (z)f(x)So we have u1 =dz and uz =dz. NOTE When evaluating these indefinite integrals we take the arbitrary constant of integration to be zero.W(z)In other words we have the single integral formulay4 (2)f(z)d.W(z)As a specific example we consider the non-homogeneous problem y" + 15y' + 50y = 25 sin (ez)(1) The general solution of the homogeneous problem (called the complementary solution, yc = ayı + byz ) is given in terms of a pair of linearly independent solutions, Yı. Y2. Here a and b are arbitrary constants.Find a fundamental set for y" + 15y' + 50y = 0 and enter your results as a comma separated listBEWARE Notice that the above set does not require you to decide which function is to be called y1 or y2 and normally the order you name them is irrelevant. But for the method of variation of parameters an order must be chosen and youneed to stick to that order. In order to more easily allow WeBWork to grade your work I have selected a particular order for y1 and y2. In order to ascertain the order you need to use please enter a choice for yı =andif your answer is marked as incorrect simply enter the other function from the complementary set. Once you get this box marked as correct then y2 =With this appropriate order we are now ready to apply the method of variation of parameters.(2) For our particular problem we have W(z) =/그– 32(z)f(z)W(z)dz =dr =r Y1 (x)f(z)dz =u2 =dz =And combining these results we arrive atYp =(3) Finally, using a and b for the arbitrary constants in yr, the general solution can then be written asy = Yc + Yp =

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In general for a non-homogeneous problem y" + p(z)y +g(z)y = f(z) assume that y1, 2 is a fundamental set of solutions for the homogeneous problem y" + p(z)y' + q(z)y = 0. Then the formula for the particular solution using the method of variation of parameters is -2(z)f(z) W(z) y1 (z)f(z) W(z) where u = and u = where W(z) is the Wronskian given by determinant |n (2) 2(z)| W(z) = |/(z) ¼(z)| -y2(z)f(z) - W(e) * Y1 (z)f(z) W(z) So we have u1 = dz and uz = dr. NOTE When evaluating these indefinite integrals we take the arbitrary constant of integration to be zero. In other words we have the single integral formula »(z) = y1 (z) /½(2)f(z) W(z) - dz + y2(z) / e y1 (z)f(z) dz W(z) As a specific example we consider the non-homogeneous problem y" + 15y + 50y = 25 sin(e) (1) The general solution of the homogeneous problem (called the complementary solution, ye = ayı + byz ) is given in terms of a pair of linearly independent solutions, y1. y2. Here a and b are arbitrary constants. Find a fundamental set for y" +15g + 50y = 0 and enter your results as a comma separated list BEWARE Notice that the above set does not require you to decide which function is to be called y1 or y2 and normally the order you name them is irrelevant. But for the method of variation of parameters an order must be chosen and you need to stick to that order. In order to more easily allow WeBWork to grade your work I have selected a particular order for y1 and y2. In order to ascertain the order you need to use please enter a choice for y1 = and if your answer is marked as incorrect simply enter the other function from the complementary set. Once you get this box marked as correct then y2 = With this appropriate order we are now ready to apply the method of variation of parameters. (2) For our particular problem we have W(z) = u1 = dz dz = W(z) * y1 (2) f(z) uz = dz dz W(z) And combining these results we arrive at Yp = (3) Finally, using a and b for the arbitrary constants in yc, the general solution can then be written as y - ye + Yp