In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 9.30 V, r, = 12 kn, and r, = 14 kn.) :10.0 µF 3.00 k2 Figure P28.67 (a) Find the steady-state current in each resistor. I, = HA I, = HA I3-kn HA (b) Find the charge Q on the capacitor. μC (c) The switch is opened at t = 0. Write an equation for the current I, in R, as a function of time. (358 µA)et/(0.170 s) (358 µA)e-t/(0.170 s) (295 µA)et/(0.170 s) (295 µA)e-t/(0.170 s) (d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value. ms
In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 9.30 V, r, = 12 kn, and r, = 14 kn.) :10.0 µF 3.00 k2 Figure P28.67 (a) Find the steady-state current in each resistor. I, = HA I, = HA I3-kn HA (b) Find the charge Q on the capacitor. μC (c) The switch is opened at t = 0. Write an equation for the current I, in R, as a function of time. (358 µA)et/(0.170 s) (358 µA)e-t/(0.170 s) (295 µA)et/(0.170 s) (295 µA)e-t/(0.170 s) (d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value. ms
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I am not sure how to complete this problem. Can you please explain A through D?
Transcribed Image Text:In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 9.30 V, r, = 12 kn, and r, = 14 kn.)
:10.0 µF
3.00 k2
Figure P28.67
(a) Find the steady-state current in each resistor.
I, =
HA
I, =
HA
I3-kn
HA
(b) Find the charge Q on the capacitor.
μC
(c) The switch is opened at t = 0. Write an equation for the current I,
in R, as a function of time.
(358 µA)et/(0.170 s)
(358 µA)e-t/(0.170 s)
(295 µA)et/(0.170 s)
(295 µA)e-t/(0.170 s)
(d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value.
ms
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