In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 8.50 V, r = 10 kn, and r2 = 16 kn.) =10.0 µF 8 3.00 k2 Figure P28.67 (a) Find the steady-state current in each resistor. I = 1.32 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. µA I2 = 4.32 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. HA I3-kA = 0 µA (b) Find the charge Q on the capacitor. 8.83 Your response differs from the correct answer by more than 10%. Double check your calculations. µC (c) The switch is opened at t = 0. Write an equation for the current IR, in R2 as a function of time. O (327 µA)e-t/(0.190 s) O (275 µA)et/(0.190 s) (275 µA)e-t/(0.190 s) O (327 µA)et/(0.190 s) (d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value. ms

In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 8.50 V, r = 10 kn, and r2 = 16 kn.) =10.0 µF 8 3.00 k2 Figure P28.67 (a) Find the steady-state current in each resistor. I = 1.32 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. µA I2 = 4.32 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. HA I3-kA = 0 µA (b) Find the charge Q on the capacitor. 8.83 Your response differs from the correct answer by more than 10%. Double check your calculations. µC (c) The switch is opened at t = 0. Write an equation for the current IR, in R2 as a function of time. O (327 µA)e-t/(0.190 s) O (275 µA)et/(0.190 s) (275 µA)e-t/(0.190 s) O (327 µA)et/(0.190 s) (d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value. ms

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

Question

In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 8.50 V, r1 = 10 kN, and r2 = 16 kN.)
10.0 µF
3.00 k2
Figure P28.67
(a) Find the steady-state current in each resistor.
I1 = 1.32
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. µA
I2 = 4.32
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. µA
I3-ko = 0
HA
(b) Find the charge Q on the capacitor.
8.83
Your response differs from the correct answer by more than 10%. Double check your calculations. µC
(c) The switch is opened at t = 0. Write an equation for the current IR, in R, as a function of time.
O (327 µA)e-t/(0.190 s)
O (275 µA)et/(0.190 s)
O (275 µA)e-t/(0.190 s)
O (327 µA)et/(0.190 s)
(d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value.
ms

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