In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. InFigure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 0. The charge onthe arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in °) does Earc = 0.95Epart? (Hint:You will probably resort to a graphical solution.)+Q+Qffe/2Ae/2(a)(b)NumberiUnits

The magnitude of the electric field produced by the point charge Q at point P is : Epart=14πε0QR2…

Answered: In Figure (a) below, a particle of…

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