In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 0. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of e (in °) does Earc = 0.95Epart? (Hint: You will probably resort to a graphical solution.) \R +Qfe/2A. +Q P e/2y (a) (b) Number i Units

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In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In
Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 0. The charge on
the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in °) does Earc = 0.95Epart? (Hint:
You will probably resort to a graphical solution.)
+Q
+Qffe/2A
e/2
(a)
(b)
Number
i
Units
Transcribed Image Text:In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 0. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in °) does Earc = 0.95Epart? (Hint: You will probably resort to a graphical solution.) +Q +Qffe/2A e/2 (a) (b) Number i Units
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