in Fig. P-509. Each tube has a cross-sectional area of 0.20 in. If the average stress In the tubes is not to exceed 10 ksi, determine the total uniformly distributed load that can be supported on a simple span 12 ft long. Neglect the effect of the webs. 12 in. 130° Figure P-509

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Q: average

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Q: Fig. P4.103 4.104 TWo 10-kN forces are applied to a 20 x 60-mm rectangular bar as shown. Determine…

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Q: Question 5 (a) The beam has the rectangular cross section shown in the Fig. Q5(a). i) Determine the…

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Q: A laminated wooden beam supports a uniform distributed loading of 12 kN/m. Allowable shear stress is…

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A: Given Normal stress 175 MPaShear stress 75 MPaAngle 45Diameters 6 mm and 10 mmTo find out Maximum…

Q: 4.19 and 4.20 Knowing that for the extruded beam shown the allowable stress is 120 MPa in tension…

A: As per Bartleby's guidelines we are supposed to answer only first question. Kindly repost other…

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Q: Q.3 For the shown simply supported beam: i) Draw the shear force and bending moment diagrams and get…

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Q: A 10 KN 1.5 m Fig. P5.15 C 1.5 m 3 kN/m 2.2 m B 100 mm 200 mm

A: Given  Concentrated load= 10 KN  Uniformly Distributed  Load= 3 KN/ m

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.